I would try but it wont let me.
We use the formula: ( a - b )^3 = a^3 - b^3 - 3ab( a - b);
a = 1000; b = 1;
999^3 = 1000^3 - 1^3 - 3·1000·1( 1000 - 1 ) = 1000000000 - 1 - 3000·999 = 1000000000 - 1 - 2997000 = 997002999;
Answer:
Well, assuming that these are cubes labeled 1-6, there is a 1/12 chance of the sum equaling 2, since they would both have to land on 1
Step-by-step explanation:
Step-by-step explanation:
Using pythagoras theorem
9^2 - 6^2 = x^2
Therefore X^2 = 81 - 36
= 45
Thus X = √45
X = 6.71
Answer:
y=42
Step-by-step explanation:
y+48+90=180
y=180-138
y=42
