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3 years ago

What is 0.000000028 in scientific notation

Mathematics

2 answers:

Papessa [141]3 years ago

8 0

2.8 X 10^-8 (........characters space so that I can post this..)

Alekssandra [29.7K]3 years ago

8 0

Answer:

The answer is:

$0.000000028=2.8*10^-^8$

Step-by-step explanation:

In order to determine the answer, we have to know about scientific notation.

In general the scientific notation is:

$a*10^b$

where:

a= rational number such that its absolute value has to satisfy:

$1\leq |a|$

b= the power of 10 required so that the scientific notation is mathematically equivalent to the original number.

We have to follow the next steps to determine the scientific notation of any number:

Move the decimal point in your number until there is only one non-zero digit to the left of the decimal point. The resulting decimal number is "a".
Count how many places you moved the decimal point. This number is "b".
If you moved the decimal to the left, "b" is positive. If you moved the decimal to the right, "b" is negative. If you did not need to move the decimal, "b" = 0.
Remove trailing 0's only if they were originally to the left of the decimal point.

Finally, the number 0.000000028 written in scientific notation is:

$a=2.8\\b=-8\\\\a*10^b=2.8*10^-^8$

$0.000000028=2.8*10^-^8$

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Answer:

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Step-by-step explanation:

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Rearranging and adding the terms in the expression and equating to zero.

f(x)= 60x² -60=0

60(x² - 1) =0

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from the zero product property we can infer that 60≠0⇒x² - 1=0

⇒(x+1)×(x-1) = 0

⇒x=±1.

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3 years ago

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sladkih [1.3K]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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3 years ago

Is 33 a prime number? Explain why or why not

viva [34]

Answer:

Step-by-step explanation:

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3 years ago

A rectangular swimming pool is bordered by a concrete patio. the width of the patio is the same on every side. the area of the s

andre [41]

Answer:

$x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)$

where

l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Explanation:

Let

x = width of the patio
l = length of the pool (w/o the patio)
w = width of the pool (w/o the patio)

Since the pool is bordered by a complete patio,

Length of the pool (with the patio)
= (length of the pool (w/o the patio)) + 2*(width of the patio)
Length of the pool (with the patio) = l + 2x

Width of the pool (with the patio)
= (width of the pool (w/o the patio)) + 2*(width of the patio)
Width of the pool (with the patio) = w + 2x

Note that

Area of the pool (w/o the patio)
= (length of the pool (w/o the patio))(width of the pool (w/o the patio))
Area of the pool (w/o the patio) = lw

Area of the pool (with the patio)
= (length of the pool (w/o the patio))(width of the pool (w/o the patio))
= (l + 2x)(w + 2x)
= w(l + 2x) + 2x(l + 2x)
= lw + 2xw + 2xl + 4x²
Area of the pool (with the patio) = 4x² + 2x(l + w) + lw

Area of the patio
= (Area of the pool (with the patio)) - (Area of the pool (w/o the patio))
= (4x² + 2x(l + w) + lw) - lw
Area of the patio = 4x² + 2x(l + w)

Since the area of the patio is equal to the area of the surface of the pool, the area of the patio is equal to the area of the pool without the patio. In terms of the equation,

Area of the patio = Area of the pool (w/o the patio)
4x² + 2x(l + w) = lw
4x² + 2x(l + w) - lw = 0 (1)

Let

a = numerical coefficient of x² = 4
b = numerical coefficient of x = 2(l + w)
c = constant term = -lw

Then using quadratic formula, the roots of the equation 4x² + 2x(l + w) - lw = 0 is given by

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\\ = \frac{-2(l + w) \pm \sqrt{(2(l + w))^2 - 4(4)(-lw)}}{2(4)} 
\\ = \frac{-2(l + w) \pm \sqrt{(4(l + w)^2) + 16lw}}{8} 
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 2lw + w^2) + 4(4lw)}}{8}
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 2lw + w^2 + 4lw)}}{8}
\\ = \frac{-2(l + w) \pm \sqrt{(4(l^2 + 6lw + w^2)}}{8}$
$= \frac{-2(l + w) \pm 2\sqrt{l^2 + 6lw + w^2}}{8} \\= \frac{2}{8}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\x = \frac{1}{4}(-(l + w) \pm \sqrt{l^2 + 6lw + w^2}) \\\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right) \text{ or }}
\\\boxed{x = -\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2} \right)}$

Since $(l + w) + \sqrt{l^2 + 6lw + w^2} \ \textgreater \ 0$ , $-\frac{1}{4}\left((l + w) + \sqrt{l^2 + 6lw + w^2}\right)$ is negative. Since x represents the patio width, x cannot be negative. Hence, the patio width is given by

$\boxed{x = \frac{1}{4}\left(-(l + w) + \sqrt{l^2 + 6lw + w^2} \right)}$

7 0

3 years ago