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steposvetlana [31]
3 years ago
7

600,000 equals how many ten thousands

Mathematics
1 answer:
Yakvenalex [24]3 years ago
5 0
Divide 600,000 by 10,000.

Equals 60!

Answer is 60.
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How many meter is a desk and a bicycle
Elan Coil [88]
It could be 1.85 meters for an adult bike.

4 0
3 years ago
Read 2 more answers
Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 ​students, she finds 2 w
irina1246 [14]

Answer:

A 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus is [0.012, 0.270].

Step-by-step explanation:

We are given that Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 ​students, she finds 2 who eat cauliflower.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

                              P.Q.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students who eat cauliflower

           n = sample of students

           p = population proportion of students who eat cauliflower

<em>Here for constructing a 95% confidence interval we have used a One-sample z-test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                   of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

Now, in Agresti and​ Coull's method; the sample size and the sample proportion is calculated as;

n = n + Z^{2}__(\frac{_\alpha}{2})

n = 24 + 1.96^{2} = 27.842

\hat p = \frac{x+\frac{Z^{2}__(\frac{\alpha}{2}_)  }{2} }{n} = \hat p = \frac{2+\frac{1.96^{2}   }{2} }{27.842} = 0.141

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

 = [ 0.141 -1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } } , 0.141 +1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } } ]

 = [0.012, 0.270]

Therefore, a 95​% confidence interval for the proportion of students who eat cauliflower on​ Jane's campus [0.012, 0.270].

The interpretation of the above confidence interval is that we are 95​% confident that the proportion of students who eat cauliflower on​ Jane's campus is between 0.012 and 0.270.

7 0
3 years ago
Kevin Horn is the national sales manager for National Textbooks Inc. He has a sales staff of 40 who visit college professors all
Oduvanchick [21]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

Given values:

38, 40, 41, 45, 48, 48, 50, 50, 51, 51, 52, 52, 53, \\\\54, 55, 55, 55, 56, 56, 57, 59, 59, 59, 62, 62, 62, \\ 63, 64, 65,66, 66, 67, 67, 69, 69, 71, 77, 78, 79, 79

Total staff=40

In point a:

To calculate the median number first we arrange the value into ascending order and then collect the even numbers of calls that were also made. Its average of the middle terms is thus the median.

The midterms =55 and 59 so,

Median = \frac{55+59}{2} = \frac{114}{2}=57

In point b:

First-quarter Q_1 = \frac{1}{4} \text{number of 8th call}

                           =\frac{1}{4} \times  30 th \\\\= 7.5 th

The first quarterlies are 7.5th \  \ that  \ is = (7+0.5)th\ \  term

therefore the multiply of 0.5  by calculating the difference of the 7th and 8th term are:

=0.5 \times 0= 0 \\\\\to Q_1 = 50+0=50 \\\\\to Q_3=\frac{3}{4} \text{number of 8th call} \\\\=\frac{3}{4} \times  30 th \\\\=22.5 \ th  = (22+0.5)th  \ \ term

therefore the it is multiply by the 0.5 for the difference of the 22nd and 23rd term:

= 0.5 \times 1=0.5 \\\\\to Q_3= 63+0.5=63.5

In point c:

First decile D_1 = \frac{1}{18} \text{number of 8th call}

= \frac{1}{10} \times  30 th \\\\= 3rd \ \ term\\\\\to D_1= 41 \\\\\to D_9= \frac{9}{10} \times  8\  th\  call\\\\=\frac{9}{10} \times  30 th \\\\=27th \ \ term\\\\\to D9 = 67

In point d:

quartiles are:

Q_1= 51.25 \\\\Q_3=66

The right answers for the decile are:

D_1=45.3 \\\\ D_9=76.4

As for D) P_{33} = 53.53will be available.

7 0
2 years ago
Where does the wraps intersect each other? <br> Y=-x+1 and <br> Y=3x+5
lora16 [44]
(-1,2) is where it will intersect
7 0
3 years ago
A line that has a slope of 1/2 and passes through the point (-4,7)
Doss [256]

Answer:

y= ½x+9

Step-by-step explanation:

Use desmos makes it easier

7 0
3 years ago
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