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ycow [4]
2 years ago
10

Simplify the following expression: 4 / y to the -3 power.

Mathematics
1 answer:
kirill [66]2 years ago
3 0
The mathematical expression of the given above is 4/y^-3 where only the denominator is raised to exponent -3. Remember that the expression x^-n may also be expressed as 1/x^n. Thus, for the given, transfer the y^-3 of the denominator to the numerator to give the final answer of 4y³.
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Endpoint: (9,-10), midpoint: (4,8)
Alika [10]

Answer:

( -1 , 26)

Step-by-step explanation:

So since you need to find the other endpoint, you would follow these steps:

1.) 4 = \frac{9 + x}{2\\}

2.) 8 = 9 + x  ( you just multiplied the 2 to the 4 to get 8)

3.) -1 = x  (just solve it like a regular equation, so just subtract 9 on both sides                  to get rid of it and that leaves you with -1 = x)

You took the x values of both points and put them in the equation.

And its the same for y

1.) 8 = \frac{-10 + y}{2}

2.) 16 = -10 + y

3.) 26 = y   (you added the 10 on both sides because the 10 was negative and that took the 10 out and so it left you with 26 = y)

5 0
3 years ago
Which number is not a whole number ? A. 8. B. -10. C. 0. D.18/3
NARA [144]

Answer:

B. -10 its a negative number

3 0
2 years ago
Given that
mina [271]

Answer:

huh?

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
100 POINT QUESTION!!!!!!!!!!!!!!!!!!!!!!!!!!!!
babunello [35]

Answer:

Ok I don't know waht you mean but the answer is

Step-by-step explanation:

Answer:

x=3/2±(√11)2

x=1.5+1.65831i

x=1.5−1.65831i

Find the Solution for

2x^22−6x+10=0

using the Quadratic Formula where

a = 2, b = -6, and c = 10

x=(−b±√(b^2−4ac))/2a

x=(−(−6)±√((−6)2−4(2)(10)))2(2)

x=(6±√(36−80))/4

x=(6±√−44)/4

The discriminant b^2−4ac<0

so, there are two complex roots.

Simplify the Radical:

x=(6±2√11 i)/4

x=6/4±(2√11 i)4

Simplify fractions and/or signs:

x=3/2±(√11)2

which becomes

x=1.5+1.65831i

x=1.5−1.65831i

4 0
2 years ago
NEED HELP QUICKLY!!
barxatty [35]
The answer is C 66 square inches
3 0
3 years ago
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