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3 years ago

Endpoint: (9,-10), midpoint: (4,8)

Mathematics

1 answer:

Alika [10]3 years ago

5 0

Answer:

( -1 , 26)

Step-by-step explanation:

So since you need to find the other endpoint, you would follow these steps:

1.) $4 = \frac{9 + x}{2\\}$

2.) 8 = 9 + x ( you just multiplied the 2 to the 4 to get 8)

3.) -1 = x (just solve it like a regular equation, so just subtract 9 on both sides to get rid of it and that leaves you with -1 = x)

You took the x values of both points and put them in the equation.

And its the same for y

1.) $8 = \frac{-10 + y}{2}$

2.) 16 = -10 + y

3.) 26 = y (you added the 10 on both sides because the 10 was negative and that took the 10 out and so it left you with 26 = y)

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The region bounded by the given curves is rotated about the specified axis. Find the volume V of the resulting solid by any meth

Lubov Fominskaja [6]

Answer:

$\frac{128\pi}{3}$ cubic units

Step-by-step explanation:

We are given that a region bounded by a curves $x=(y-7)^2$

x=4 and about y=5

We have to find the value of volume of the resulting solid

To find the volume of resulting solid we are using cylinder method

Substitute the values of x then we get

$(y-7)^2=4$

$y-7=\pm2$

y-7=2 and y-7=-2

y=7+2=9 and y=-2+7=5

Radius of cylinder =r=y-5

and height =h= $4-(y-7)^2=4-y^2-49+14 y=-y^2+14 y -45$

Using cylinder method and integrate along y -axis from y=5 to y=9

Volume = $\int_{a}^{b}2\pi r h dy=\int_{5}^{9}2\pi(y-5)(-y^2+14 y -45) dy$

volume= $2\pi\int_{5}^{9}(-y^3+19y^2-115y+225)dy$

Volume = $2\pi[-\frac{y^4}{4}+19\frac{y^3}{3}-115\frac{y^2}{2}+225y]^9_5$

Volume = $2\pi[-\frac{6561}{4}+\frac{625}{4}+19(\frac{729-125}{3})-115(\frac{81-25}{2})+225(9-5)]$

Volume= $2\pi(-1484+\frac{11476}{3}-3220+900)$

Volume = $2\pi(\frac{11476}{3}-3804)$

Volume = $2\pi(\frac{11476-11412}{3})=\frac{128\pi}{3}$

Hence, volume of resulting solid = $\frac{128\pi}{3}$ cubic units

3 0

3 years ago

find two positive even consecutive integers such that a square of the smaller integer is 10 more than the larger integer

nalin [4]

Answer:

the two positive consecutive integers are 4 and 6.

Step-by-step explanation:

Let the smaller integer be s; then s^2 = (s + 2) + 10.

Simplifying, s^2 - s - 2 - 10 = 0, or

s^2 - s - 12 = 0.

Solve this by factoring: (s - 4)(s + 3) = 0.

Then s = 4 and s = -3.

If the first even integer is 4, the next is 6. We omit s = -3 because it's not even.

The smaller integer is 4. Does this satisfy the equation s^2 = (s + 2) + 10?

4^2 = (4 + 2) + 10 True or False?

16 = 6 + 10 = 16.

True.

So the two positive consecutive integers are 4 and 6.

6 0

3 years ago

43 5/12 x 11 Please help

zzz [600]

The perimeter is the sum of side lengths. Opposite sides of a rectangle are the same length, so the perimeter is
P = 11 +43 5/12 +11 +43 5/12
= 2(11 +43 5/12)
= 2(54 5/12)
P = 108 5/6 . . . . feet

The area is the product of length and width. It doesn't matter which of the given dimensions you consider length or width, since you multiply them either way.
A = 11 * 43 5/12
= 473 +55/12
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3 years ago

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Scorpion4ik [409]

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3 years ago

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Elza [17]

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