Can someone help me with both # 3

Mathematics

1 answer:

Sidana [21]4 years ago

4 0

To answer this question I need a problem. Have a fabulous day,you are awesome!

You might be interested in

Cube root of - 1000p^12q^3

aleksley [76]

$\bf \sqrt[3]{-1000p^{12}q^3}~~
\begin{cases}
1000=10^3\\
(-1)^3=-1\cdot -1\cdot -1\\
\qquad -1\\
p^{12}=p^{4\cdot 3}\\
\qquad (p^4)^3
\end{cases}\implies \sqrt[3]{(-1)^3(10)^3(p^4)^3q^3}
\\\\\\
(-1)(10)p^4q\implies -10p^4q$

7 0

3 years ago

Identify the values of m and b of the linear function y = mx + b, graphed below.

Varvara68 [4.7K]

<h2>Finding the slope and y-intercept of a line given the graph</h2><h3>Answer:</h3>

$b = 4$

$m = -\frac{1}{3}$

<h3>Step-by-step explanation:</h3>

An equation of a line written in its Slope-intercept Form, $y = mx +b$ , has $b$ as its $y$ -intercept and $m$ as its slope.

$b$ or the $y$ -intercept is the $y$ -coordinate when $x = 0$ . On the given line, we can see that when $x = 0$ , $y = 4$ . It's $y$ -intercept is the point $(0,4)$ so $b = 4$ .

The slope, $m$ , of the line can be calculated by $\frac{y_2 -y_1}{x_2 -x_1}\\$ where $x_n$ and $y_n$ is the $xy$ -coordinates of any point $n$ on the line. In the given line, we can see that $(5,3)$ is on the line so this can be point $1$ . $(0,4)$ is also on the line (yes, you can also use the $y$ -intercept in calculating the slope of the line) so this can be our point $2$ .