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TEA [102]
4 years ago
5

Which ordered pairs make both inequalities true? Check all that apply. y < 5 x + 2 y > 1/2 x + 1

Mathematics
1 answer:
anzhelika [568]4 years ago
8 0
For (-3, 2): 2 > 5(-3) + 2; 2 > -15 + 2; 2 > -13 (i.e. not correct)
for (-1, 3): 2 > 5(-1) + 2; 2 > -5 + 2; 2 > -3 (i.e. not correct)
for (0, 2): 2 = 5(0) + 2; 2 = 0 + 2; 2 = 2 (i.e. not correct)
for (1, 2): 2 < 5(1) + 2; 2 < 5 + 2; 2 < 7 (i.e. correct): 2 > 1/2(1) + 1; 2 > 1/2 + 1; 2 > 3/2 (i.e. correct)
for (2, -1): -1 < 5(2) + 2; -1 < 10 + 2; -1 < 12 (i.e. correct): -1 < 1/2(2) + 1; -1 < 1 + 1; -1 < 2 (i.e. not correct)
for (2, 2): 2 < 5(2) + 2; 2 < 10 + 2; 2 < 12 (i.e. correct): 2 = 1/2(2) + 1; 2 = 1 + 1; 2 = 2 (i.e. not correct)

Therefore, both ineaqualities are tru for only the ordered pair (1, 2)
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Find the coordinates of the midpoint of the segment whose endpoints are H(5, 13) and K(7, 5). (12, 18)
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\text{The formula of the midpoint of segment AB:}\\\\\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right).\\\\\text{We have the points}\ H(5,\ 13)\ \text{and}\ K(7,\ 5).\ \text{Substitute:}\\\\x=\dfrac{5+7}{2}=\dfrac{12}{2}=6\\\\y=\dfrac{13+5}{2}=\dfrac{18}{2}=9\\\\Answer:\ \boxed{(6,\ 9)}

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