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masya89 [10]
3 years ago
10

If a sodium atom lost one of its electrons and a chlorine atom gained it, what kind of bond would be formed between sodium and c

hlorine?
a. ionic
b. valence
c. metallic
d. covalent
Chemistry
2 answers:
Vikki [24]3 years ago
4 0
With no doubt, this type of bond would be ionic.

An ionic bond is when we transfer electrons. This means that the atoms would gain a charge.

Na+Cl- would be the resulting compound because:-

Na (sodium) loses : which means it would GAIN a positive charge.

Cl (chlorine) gains: which means it GAINS a negative charge.

Natasha_Volkova [10]3 years ago
3 0
This would be an ionic bond.  Ionic bonds form between metals and nonmetals due to the relatively large different in electronegativities where nonmetals are more electronegative than metals.  This difference in electronegativities makes it so that the metal gives up the electron to make an octet and the nonmetal gains the electron to make an octet (there is no sharing of the electron).  The metal becomes a cation while the nonmetal becomes a anion and their opposite electric charges keep them together.

I hope this helps let me know in the comments if anything is unclear.
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Molar \ solubility=3.12x10^{-5}M

Explanation:

Hello,

In this case, for the dissociation of calcium fluoride:

CaF_2(s)\rightleftharpoons Ca^{2+}+2F^-

The equilibrium expression is:

Ksp=[Ca^{2+}][F^-]^2

In such a way, via the ICE procedure, including an initial concentration of calcium of 0.01 M (due to the calcium nitrate solution), the reaction extent x is computed as follows:

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Thus, the molar solubility equals the reaction extent x, therefore:

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