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3 years ago

2. A sample of iron has the dimensions of 2.0 cm x 3.0 cm x

Chemistry

1 answer:

dsp733 years ago

6 0

Answer:

first change cm to m and g to kg so you will find the volume first which is 0.02 by 0.03 by 0.02 your answer is 0.000012 m . using the formula density=mass/volume take 0.094/ 0.00012 then divide

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How many significant figures are needed in the answer when 1.31m is multiplied by 6.5 m

dmitriy555 [2]

Answer:

two

Explanation:

The number of significant figures needed in the answer is 2.

This is because when finding the products of two numbers, the result is as accurate as the least number of significant figures of the numbers being multiplied.

Here the numbers being multiplied are;

1.31m

6.5m

1.31m has 3 significant figures

6.5m has 2 significant figures.

So, the product will have 2 significant figures

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2 years ago

The brightness of a star depends on its _____ a. color b. composition of atmosphere c. distance from Earth, and stars that are c

Yanka [14]

Answer:

Either B or C. Composition or the Distance from the Earth.

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3 years ago

Why are metal containers not used for storing acids

kaheart [24]

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3 years ago

Question 14 A student dissolves 1.5g of styrene C8H8 in 225.mL of a solvent with a density of 1.02/gmL . The student notices tha

Yuki888 [10]

We must to know:

Cm = molarity = niu / Vs, when the niu = no. of moles and Vs = Volume of solution

the no. niu = mass / molecular mass of substance

molecular mass of C8H8 = 12x8+8x1 = 104 g/mol

=> niu = 1,5 / 104 = 0,0144 moles C8H8

=> Cm = 0,0144/0,225 = 0,06 mol/L

Cmm = molality = niu (C8H8) / mass of solvent (kg)

=> p = mass / V => mass (solvent) = p x V

=> 225 x 1,02 = 229,5 g solvent = 0,2295 kg solvent

=> Cmm = 0,0144 / 0,229,5 = 0,063

8 0

3 years ago

Read 2 more answers

Determine the reducing agent in the following reaction. Explain your answer. 2 Li(s) + Fe(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + Fe(s)

Brilliant_brown [7]

The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).

The general reaction is:

2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) (1)

We can write the above reaction in two reactions, one for oxidation and the other for reduction:

Oxidation reaction

Li⁰(s) → Li⁺(aq) + e⁻ (2)

Reduction reaction

Fe²⁺(aq) + 2e⁻ → Fe⁰(s) (3)

We can see that Li⁰ is oxidizing to Li⁺ (by losing one electron) in the lithium acetate (reaction 2) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by gaining two electrons) (reaction 3).

We must remember that the reducing agent is the one that will be oxidized by reducing another element and that the oxidizing agent is the one that will be reduced by oxidizing another species.

In reaction (1), the reducing agent is Li (it is oxidizing to Li⁺), and the oxidizing agent is Fe(CH₃COO)₂ (it is reducing to Fe⁰).

Therefore, the reducing agent in reaction (1) is lithium (Li).

Learn more here:

brainly.com/question/10547418?referrer=searchResults

brainly.com/question/14096111?referrer=searchResults

I hope it helps you!

3 0

2 years ago