A rectangle has a width w that is 5 units longer than its length l. Which equation expresses the rectangle's area, A?

2 answers:

7 0

There are several information's already given in the question. Based on those information's the answer to the question can be easily determined.
Length of the rectangle in question = l
Width of the rectangle in question = l + 5
Then
Area of the rectangle = l * (l + 5)
= l^2 + 5l
I hope that this is the answer that has come to your help.

Hunter-Best [27]3 years ago

5 0

Answer:

Area $= x* (x+5)\\= x^2 + 5x$

Explanation:

Let the length of rectangle be equal to "x" units

Given, width w that is 5 units longer than its length l

Hence, the equation for width of rectangle in terms of "x" is

$w = x+5$

Area of the rectangle is given by

$l * w$

where

"l" is the length of the rectangle.

and "w" is the width of the rectangle.

Substituting the value of both length and width in terms of "x" in above equation, we get -

Area $= x* (x+5)\\= x^2 + 5x$

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max2010maxim [7]

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