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3 years ago

Think about what you know about perimeter and area. Describe hoe to find the perimeter and area of your classroom.

2 answers:

7 0

You would have to measure the side lengths of the classroom then use the normal formulas to find area and perimeter of a rectangle or square
(A= l•w)
(P=l+l+w+w)
Only use those formulas if the room is a regular rectangle or square.

ivanzaharov [21]3 years ago

5 0

Answer:

Perimeter : This is defined as the total measurement of all the sides of any closed figure. As given, it is a classroom, so the shape of the classroom should be either square or rectangle.

Perimeter of a rectangle is = 2(length+width)

Perimeter of a square is = 4*side length

Area is defined as the number of unit squares that can be contained in a closed figure.

So, area of a rectangle is given as = length*width

Area of a square is given as = side length*side length.

In general, the classrooms have these shapes only.

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If a line passes through (2, 4) and (5,-4), what is the slope?

Mila [183]

Answer:

So the slope is -8/3

Step-by-step explanation:

to find the slope you have to use m = y2-y1/x2-x1

so lets plug in our numbers

m = - 4- 4/5-2

= -8/3

So the slope is -8/3

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2 years ago

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3 years ago

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3 years ago

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2 years ago

An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba

madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

X = a person is overweight

Y = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688$

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

$P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312$

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

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2 years ago