Answer:
a dominant mutation
Explanation:
A monohybrid testcross is a cross-breeding experiment used to determine if an individual exhibiting a dominant phenotype is homo-zygous dominant or heterozygous for a particular phenotypic trait (in this case, wing length). In a monohybrid testcross, a 1:1 phenotypic ratio shows that the dominant parental phenotype was a heterozygote for a single gene that has complete dominance. Moreover, a 3:1 ratio in the F2 is expected of a cross between heterozygous F1 individuals, which means that 75% of individuals with short wings have the dominant allele that masks the expression of the long-wing trait (i.e. the recessive allele).
Answer:
1/2
Explanation:
You have a 1/2 chance of having a boy and a 1/2 chance of having a girl.
Unless the question specifies whether or not there is a mutation present with the male parent, it is safe to assume there is a 50/50 shot of having a boy or girl.
Answer:
B. 2 : 0 : 2
Explanation:
In a punnet square, the alleles would be Tt, Tt, tt, tt. So, you have 2/4 or 50% of the genotype Tt, and 2/4 or 50% of the genotype tt.
there is a zero percent chance do to the sterilization and cleaning of all equipment as well as it being illegal to reuse needles in hospitals
Answer:
Learning the dominance of alleles
Explanation:
