Given:
The data values are
11, 12, 10, 7, 9, 18
To find:
The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.
Solution:
We have,
11, 12, 10, 7, 9, 18
Arrange the data values in ascending order.
7, 9, 10, 11, 12, 18
Divide the data in two equal parts.
(7, 9, 10), (11, 12, 18)
Divide each parenthesis in 2 equal parts.
(7), 9, (10), (11), 12, (18)
Now,
Median = 
=
=
Lowest value = 7
Greatest value = 18
Lower quartile = 9
Upper quartile = 12
Interquartile range (IQR) = Upper quartile - Lower quartile
= 12 - 9
= 3
Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.
The time on this clock is 11:54
9514 1404 393
Answer:
- Angle 1 = 139°
- Angle 2 = 41°
- x = 29; exterior angle = 131°
Step-by-step explanation:
These problems let you make use of the fact that the sum of the remote interior angles is equal to the exterior angle.
__
1. 53° +86° = ∠1
139° = ∠1
__
2. ∠2 +92° = 133°
∠2 = 133° -92°
∠2 = 41°
__
3. (x +9)° +93° = (4x+15)°
87 = 3x . . . . . . . . . . . . . . . . subtract x+15°
29 = x . . . . . . . divide by 3
The exterior angle is ...
(4x +15)° = (4·29 +15)° = 131° . . . exterior angle
Both are correct they just chose a different variable to solve for first. they will both get correct answers if they do the rest correctly.