Answer:
D
Step-by-step explanation:
B has a y-intercept of 4, greater than A's y-intercept of -4. This means that D is correct.
The piece-wise linear functions can be written as follows:
.
.
.
<h3>What is a linear function?</h3>
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
For x equal or less than -2, the line passes through (-3,-3) and (-2,-2), hence the rule is:
.
For x greater than -2 up to 1, the y-intercept is of -7, and the line also passes through (1,-8), hence the rule is:
.
For x greater than 1, the function goes through (2,-5) and (3,-3), hence the slope is:
m = (-3 - (-5))(3 - 2) = 2.
The rule is:
y = 2x + b.
When x = 2, y = -5, hence:
-5 = 2(2) + b
b = -9.
Hence:
.
More can be learned about linear functions at brainly.com/question/24808124
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To find our solution, we can start off by creating a string of 27 boxes, all followed by the letters of the alphabet. Underneath the boxes, we can place 6 pairs of boxes and 15 empty boxes.The stars represent the six letters we pick. The empty boxes to the left of the stars provide the "padding" needed to ensure that no two adjacent letters are chosen. We can create this -

Thus, the answer is that there are

ways to choose a set of six letters such that no two letters in the set are adjacent in the alphabet. Hope this helped and have a phenomenal New Year!
<em>2018</em>
The answer is C. Have a nice day.
Answer:
1. 208 in^2
Step-by-step explanation:
1. We can break the shape up into a rectangle in the middle and 2 triangles on either side of said rectangle.
The dimensions of the rectangle are 8 in by 20 in, and we only know one leg of the triangle as well as the hypotenuse.
If we know one leg and the hypotenuse we can use the pythagorean theormed to sovle for the other side and get 6 in.
So we have
(8 * 20) + 2((1/2)(6)(8))
160 + 48
208 in^2