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Hunter-Best [27]
3 years ago
5

The perimeter of a rectangle is 68 ft. Find the dimensions of the rectangle if the ratio of the length to the width is 9 : 8. Wh

ich of the following would be the best equation to use to solve this problem?
Mathematics
1 answer:
omeli [17]3 years ago
3 0
The perimeter of a rectangle is 

P = 2w +2l
P = 68 ft

and given the ratio l/w = 9/8 from this result 8l = 9w so l = (9w)/8

P = 2w +2l

68 = 2w +2((9w)/8)

68 = 2w +9w/4

4*68 = 8w +9w

272 = 17w

w = 272/17

w = 16 

so than we know that w=16 so than the length will be 

l = (9w)/8

l = 9*16/8

l = 9*2

l = 18

so than we know that 

l = 18
w = 16
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65.<br> Evaluate a-b+c for?
Rama09 [41]

Answer:

From the problem, the answer to the equation is 5 1/10

Step-by-step explanation:

First, let's gather the information from the problem.

<em>a = 4 1/5 (also can be turned into 21/5)</em>

<em>b = 2 7/20 (also can be turned into 47/20)</em>

<em>c = 3 1/4 (also can be turned into 13/4)</em>

Now, plug in the numbers using the improper fractions.

21/5 - 47/20 + 13/4

Turn the denominators into the same number.

84/20 - 47/20 + 65/20

Subtract 84/20 and 47/20.

37/20 + 65/20

Add 37/20 and 65/20.

102/20 or 5 1/10

So, your answer to this equation is 5 1/10.

7 0
3 years ago
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Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
HELP ASAP PLEASE!!!!!
nataly862011 [7]

The answer is A. a=(-1) b=(7)

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4 years ago
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95 hope this helps!!!!!!!!




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3 years ago
In desperate need. for answer 11 and 12.
Thepotemich [5.8K]
11. The answer would be 3:30 because in all it took her 3:50 minutes so subtract from 7:20 you get 3:30
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