The perimeter of a rectangle is 68 ft. Find the dimensions of the rectangle if the ratio of the length to the width is 9 : 8. Wh
ich of the following would be the best equation to use to solve this problem?
1 answer:
The perimeter of a rectangle is
P = 2w +2l
P = 68 ft
and given the ratio l/w = 9/8 from this result 8l = 9w so l = (9w)/8
P = 2w +2l
68 = 2w +2((9w)/8)
68 = 2w +9w/4
4*68 = 8w +9w
272 = 17w
w = 272/17
w = 16
so than we know that w=16 so than the length will be
l = (9w)/8
l = 9*16/8
l = 9*2
l = 18
so than we know that
l = 18
w = 16
You might be interested in
Rewrite the inequality without the absolute value
-18 < x - 13 < 18
Add 13 to the whole equation
-18 + 13 < x < 18 + 13
Simplify
<u>-5 < x < 31</u>
Answer:
yes
Step-by-step explanation:
f(x) = x^2 -1
Hope it helps!!
⇒ s = a+b+c2=5+12+132 a + b + c 2 = 5 + 12 + 13 2 = 15 cm.
Area of the base = √s(s−a)(s−b)(s−c)
= √15×10×3×2 15 × 10 × 3 × 2 cm2 = 30 cm2
