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Ira Lisetskai [31]
3 years ago
10

Joey is building a frame for a sandbox. The sandbox is going be have the

Mathematics
2 answers:
Ksivusya [100]3 years ago
5 0
The quadrilateral is a rectangle
Airida [17]3 years ago
4 0

Answer:

The quadrilateral would be a rectangle.

explanation:

since opposite sides are equal, the diagonals are bound to equal as well, since the whole point of a diagonal is to go from one point to it's opposite corner.

I hope I helped, And please rate me 5 stars!

You might be interested in
How many times does 3 go into 42
trasher [3.6K]

3 goes into 42 14 times


3 0
3 years ago
In an anthropology class there are 77 anthropology majors and 1414 non-anthropology majors. 55 students are randomly selected to
Nata [24]

Answer:

P = 0.9989

Step-by-step explanation:

In order to do this, I will use the following numbers to make the calculations easier. In this case, We'll say that we have 7 majors and 14 non majors anthopology to present a topic.

This means that in the class we have 21 students.

Now, we choose 5 of them, and we want to know the probability that 1 of them is non major.

First, we need to calculate the number of ways we can select the students in all cases, and then, the probability.

First, we'll use the combination formula, to calculate the number of ways we can select the 5 students out of the 21. We use combination, because it does not matter the order that the students are selected.

C = m! / n!(m - n)!

Where:

m: number of students

n: number of selected students out of m.

With this expression we will calculate first, how many ways we can choose the 5 students out of 21:

C1 = 21! / 5!(21-5)! = 20,349

Now let's calculate the number of ways you can get the all 5 students are non majors:

C2 = 14! / 5!(14 - 5)! = 2002

Now we need to know the number of ways we can get 4 non majors and 1 major:

C3 = C3' * C3''

C3' represents the number of ways we can get 4 non majors and the C3'' represents the number of ways we can get 1 major.

C3' = 14! / 4!(14 - 4)! = 1,001

C3'' = 7! / 1!(7 - 1)! = 7

C3 = 1001 * 7 = 7,007 ways to get 4 non majors and 1 major

Now the way to get 3 non majors and 2 majors, we do the same thing we do to get 4 non majors and 1 major, but changing the numbers. Then the way to get 2 non majors and 3 majors, and finally 1 non major and 4 majors:

3 non majors and 2 majors:

C4 = C4' * C4'' = [14! / 3!(14 - 3)!] * [7! / 2!(7 - 2)!] = 7,644

2 non majors and 3 majors:

C5 = C5' * C5'' = [14! / 2!(14 - 2)!] * [7! / 3!(7 - 3)!] = 3,185

1 non major and 4 majors:

C6 = C6' * C6'' = [14! / 1!(14 - 1)!] * [7! / 4!(7 - 4)!] = 490

Finally to know the probability of getting 1 out of the 5 to be non major, we have to sum all the previous results, and divide them by the ways we can choose the 5 students (C1):

P = 2,002 + 7,007 + 7,644 + 3,185 + 490 / 20,349

P = 0.9989

5 0
3 years ago
Need help with a math question
Darya [45]

Answer:

Z =7

Step-by-step explanation:

The middle segment theorem of a triangle says that: A middle segment connecting two sides of a triangle is parallel to the third side and is half its length.

In this case, the middle segment connecting two sides of a triangle is Z.

This means that

Z = 0.5(14)

Finally we have that:

Z =7

The length of the middle segment is 7 units

4 0
3 years ago
Find angles EFG pleaseee
Bumek [7]

Answer:

50 degrees.

Step-by-step explanation:

Angle FGE = 180-(7x+18) because angles on a straight line add up to 180 degrees.

Angle EFG = 180-38-(180-(7x+18))=6x-10 (Angles in a triangle add up to 180)

180-38-\left(-7x+162\right)=6x-10

180-38+7x-162=6x-10

7x-20=6x-10

Add 20 to both sides:

7x-20+20=6x-10+20

7x=6x+10

Subtract 6x from both sides:

7x-6x=6x+10-6x

x=10

Angle EFG=6x-10=6(10)-10=60-10=50

3 0
3 years ago
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05 - O gráfico a seguir mostra a prevalência de obesidade da
dezoksy [38]
I don’t know spanish sorry
3 0
3 years ago
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