<span>c) 45 degrees west of south</span>
Answer:
Step-by-step explanation:
We have the equations
4x + 3y = 18 where x = the side of the square and y = the side of the triangle
For the areas:
A = x^2 + √3y/2* y/2
A = x^2 + √3y^2/4
From the first equation x = (18 - 3y)/4
So substituting in the area equation:
A = [ (18 - 3y)/4]^2 + √3y^2/4
A = (18 - 3y)^2 / 16 + √3y^2/4
Now for maximum / minimum area the derivative = 0 so we have
A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0
-3/8 (18 - 3y) + √3 y /2 = 0
-27/4 + 9y/8 + √3y /2 = 0
-54 + 9y + 4√3y = 0
y = 54 / 15.93
= 3.39 metres
So x = (18-3(3.39) / 4 = 1.96.
This is a minimum value for x.
So the total length of wire the square for minimum total area is 4 * 1.96
= 7.84 m
There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.
Where what assignment are you talking about
-2x^2 + 5x -3 =0
Find the discriminate:
In the given formula a = -2, b = 5 and c = -3
The discriminate is found using the formula b^2 - 4(ac)
Replace the letters with their values:
5^2 - 4(-2*-3)
25 - 4*6
25-24 = 1
When the discriminate is greater than or equal to 0, there are two real solutions.
The answer is c) 2
Answer:
Jane's age = X
In 2 years time = X + 2
In 5 years time = X + 5
Step-by-step explanation:
Answer from Gauth math