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3 years ago

8

Help asap pleaseeee !!!!!!

1 answer:

natima [27]3 years ago

8 0

Answer:

C. ⅓ × (8 + 7) + 12

Step-by-step explanation:

Let's translate each statement given to numerals and symbols first:

Twelve => 12

One-third => ⅓

Sum of 8 and 7 => (8 + 7)

Representing this statement altogether will be:

⅓ of (8 + 7) = ⅓ × (8 + 7)

If 13 is added, we would get:

⅓ × (8 + 7) + 12

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How far from an airport can an airplane fly and return in 8 hours, if it's outgoing speed is 160 km per hour and it's returning

PilotLPTM [1.2K]

<span>speed = distance/time
total time is 8 hours

outgoing speed is 160 km per hour,
so time = d/160

</span><span>returning speed is 240 km per hour,
so time = d/240

d/160 + d/240 = 8

3d/480 + 2d/480 = 8
5d/480 = 8
5d =480 (8)
5d = 3840
d=3840/5
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answer: so the distance is 768 km</span>

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3 years ago

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2 years ago

What is 100/298 written in its simplest form

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3 years ago

In this problem, x = c1 cos t + c2 sin t is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solut

Norma-Jean [14]

Differentiate the given solution:

$x=C_1\cos(t)+C_2\sin(t) \implies x'=-C_1\sin(t)+C_2\cos(t)$

Now, given that <em>x</em> (<em>π</em>/4) = √2/2 … (I'm assuming there are symbols missing somewhere) … you have

$\dfrac{\sqrt2}2=C_1\cos\left(\dfrac\pi4\right)+C_2\sin\left(\dfrac\pi4\right)$

$\implies\dfrac1{\sqrt2} = \dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}$

$\implies C_1+C_2=1$

Similarly, given that <em>x'</em> (<em>p</em>/4) = 0, you have

$0=-C_1\sin\left(\dfrac\pi4\right)+C_2\cos\left(\dfrac\pi4\right)$

$\implies 0=-\dfrac{C_1}{\sqrt2}+\dfrac{C_2}{\sqrt2}$

$\implies C_1=C_2$

From this result, it follows that

$C_1+C_2=2C_1=1 \implies C_1=C_2=\dfrac12$

So the particular solution to the DE that satisfies the given conditions is

$\boxed{x=\dfrac12\cos(t)+\dfrac12\sin(t)}$

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2 years ago