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Oxana [17]
3 years ago
11

What is the difference between 1261/4 and 782/3

Mathematics
1 answer:
mezya [45]3 years ago
4 0

Answer:

A. 57 7/12 B. 58 5/12 C. 47 7/12 D. 48 1/3

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Three groups of students used different methods to estimate the diagonal length of a patio in feet. Their results were:
podryga [215]
F14.33 1425,413 that’s the right number
5 0
3 years ago
Ella uses 3 inches of ribbon for each key chain she makes. How many key chains can she make with 4 yards of ribbon?
Marina CMI [18]

Answer:

48

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP ASAP!!!!
musickatia [10]
Let us model this problem with a polynomial function.

Let x =  day number (1,2,3,4, ...)
Let y = number of creatures colled on day x.

Because we have 5 data points, we shall use a 4th order polynomial of the form
y = a₁x⁴ + a₂x³ + a₃x² + a₄x + a₅

Substitute x=1,2, ..., 5 into y(x) to obtain the matrix equation
|   1     1    1    1    1  |  | a₁ |      | 42 |
| 2⁴  2³  2²  2¹  2⁰  |  | a₂ |      | 26 |
| 3⁴  3³  3²  3¹  3⁰   |  | a₃ |  =  | 61 |
| 4⁴  4³  4²  4¹  4⁰   |  | a₄ |      | 65 |
| 5⁴  5³  5²  5¹  5⁰  |  | a₅ |      | 56 |

When this matrix equation is solved in the calculator, we obtain
a₁ =      4.1667
a₂ =  -55.3333
a₃ =  253.3333
a₄ =  -451.1667
a₅ =   291.0000

Test the solution.
y(1) = 42  
y(2) = 26
y(3) = 61
y(4) = 65
y(5) = 56

The average for 5 days is (42+26+61+65+56)/5 = 50.
If Kathy collected 53 creatures instead of 56 on day 5, the average becomes
(42+26+61+65+53)/5 = 49.4.

Now predict values for days 5,7,8.
y(6) = 152
y(7) = 571
y(8) = 1631


3 0
3 years ago
Read 2 more answers
NEED HELP PLEASE!!!!
Masja [62]

Answer:

Yes

Step-by-step explanation:

\sqrt{\frac{2x}{9} }={\frac{\sqrt{2x} }\sqrt{} {9} }  =\frac{\sqrt{2x} }{3}=\frac{1}{3}\sqrt{2x}

3 0
3 years ago
Make a flow chart showing that the triangles below are similar. NO LINKS OR CRAZY LANGUAGES.!!!!!!​
pantera1 [17]

Answer: See the attached image

You have the correct idea for the boxes you've filled out. For the first three boxes in column 1, I would be specific which segments you are dividing. So for instance, in the first box, it would be EG/EB = 55/11 = 5. Then the second box would be EF/EC = 35/7 = 5, and so on. The order of the boxes doesn't matter. The three boxes then combine together to help show that the triangles are similar. Specifically \triangle EFG \sim \triangle ECB. The order of the letters is important to help show how the angles pair up and how the sides pair up. We use the SSS similarity theorem here.

The second problem is the same idea, but we use one pair of congruent angles. So we'll use the SAS similarity theorem this time.

8 0
3 years ago
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