See the attached figure.
<span>ad is a diameter of the circle with center p
</span>
∵ pd = radius = 7 ⇒⇒⇒ ∴ ad = 2 * radius = 2 * 7 = 14
∵ ae = 4 ⇒⇒⇒ ∴ ed = ad - ae = 14 - 4 = 10
∵ ad is a diameter
Δ acd is a triangle drawn in a half circle
∴ Δ acd is a right triangle at c
∵ bc ⊥ ad at point e
By applying euclid's theorem inside Δ acd
∴ ce² = ae * ed
∴ ce² = 4 * 10 = 40
∴ ce = √40 = 2√10 ≈ 6.325
Answer:
I think it's C. sjisebd ddhisuaja. usually get ebe.
The <u>answer would be 6</u>. The number line which shows you the number 6 or any solution for 6 would be your answer.
The <u>correct answers</u> are:
6.5 cm = 65.00001052 torr
6.5 cm = 8665.93 Pa
6.5 cm = 0.08552632119 atm
Explanation
The conversion rate from centimeters mercury (cm Hg) to torr is
1 torr = 0.099999983814461 cm.
We have 6.5 cm; this means to convert we divide:
6.5/0.099999983814461 = 65.00001052
The conversion rate from cm Hg to Pascals (Pa) is
1 cm = 1333.22 Pa
We have 6.5 cm; this means to convert we multiply:
6.5(1333.22) = 8665.93
The conversion rate from cm Hg to atmospheres (atm) is
1 atm = 75.999995199606 cm
We have 6.5 cm; this means to convert we divide:
6.5/75.999995199606 = 0.08552632119
Answer:

Step-by-step explanation:
Given
Bisector: QS


Required
Determine PQR
Since PQR is bisected to PQS and RQS, we have that

Substitute expressions for PQS and RQS

Collect Like Terms


Divide both sides by 3

Solving for PQR;



Substitute 2 for x


