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KiRa [710]
3 years ago
12

You invest $500 in an account that has an annual interest rate of 8%, compounded weekly for 12 years. What is the equivalent int

erest rate and how many times will the money be compounded? How much will you have?
Mathematics
1 answer:
pochemuha3 years ago
5 0

Answer:

i_m=8.322\%\\\\624 \ compoundings\\\\A_{12}=\$1,304.88

Step-by-step explanation:

#The equivalent interest rate per annum is equal to the effective interest rate.

-Given 8% compounded weekly( Take 1 yr=52 weeks) the effective interest rate is calculated as:

i_m=(1+i/m)^m-1\\\\\#where\\i=stated \ interest\  rate\\m=number \ of \ compoundings \ per \ year\\\\\therefore i_m=(1+0.08/52)^{52}-1\\\\=0.08322\approx 8.322\%

Hence, the equivalent interest rate is 8.322%

-Assuming one year has 52 weeks,   the number of compoundings will be :

=compoundings \ per \ year \times \ no \ of \ years\\\\=52\times 12\\\\=624\ compoundings

-The investment amount after 12 years is calculated as:

A=P(1+i_m)^n, n=number \ of \ years\\\\=500(1.08322)^{12}\\\\=1304.88

Hence, the amount after 12 years is $1304.88

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In circle pp, ad¯¯¯¯¯ad¯ is a diameter and bc¯¯¯¯¯bc¯ is perpendicular to ad¯¯¯¯¯ad¯ at ee. if pd=7pd=7 and ae=4ae=4, find cece.
kvv77 [185]
See the attached figure.

<span>ad is a diameter of the circle with center p
</span>
∵ pd = radius = 7 ⇒⇒⇒ ∴ ad = 2 * radius  = 2 * 7 = 14
∵ ae = 4 ⇒⇒⇒ ∴ ed = ad - ae = 14 - 4 = 10
∵ ad is a diameter
Δ acd is a triangle drawn in a half circle
∴ Δ acd is a right triangle at c
∵ bc ⊥ ad at point e
By applying euclid's theorem inside Δ acd
∴ ce² = ae * ed
∴ ce² = 4 * 10 = 40
∴ ce = √40 = 2√10 ≈ 6.325


3 0
3 years ago
EXERCISE 3.4
Lisa [10]

Answer:

I think it's C. sjisebd ddhisuaja. usually get ebe.

7 0
3 years ago
Which number line represents the expression 7 + (−3) + (−2) +4?
vekshin1

The <u>answer would be 6</u>. The number line which shows you the number 6 or any solution for 6 would be your answer.

3 0
3 years ago
A sealed-tube manometer can be used to measure pressures below atmospheric pressure. The tube above the mercury is evacuated. Wh
sp2606 [1]
The <u>correct answers</u> are:

6.5 cm = 65.00001052 torr
6.5 cm = 8665.93 Pa
6.5 cm = 0.08552632119 atm

Explanation

The conversion rate from centimeters mercury (cm Hg) to torr is
1 torr = 0.099999983814461 cm.

We have 6.5 cm; this means to convert we divide:
6.5/0.099999983814461 = 65.00001052

The conversion rate from cm Hg to Pascals (Pa) is
1 cm = 1333.22 Pa

We have 6.5 cm; this means to convert we multiply:
6.5(1333.22) = 8665.93

The conversion rate from cm Hg to atmospheres (atm) is
1 atm = 75.999995199606 cm

We have 6.5 cm; this means to convert we divide:
6.5/75.999995199606 = 0.08552632119
7 0
3 years ago
Read 2 more answers
QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is
soldi70 [24.7K]

Answer:

PQR = 20

Step-by-step explanation:

Given

Bisector: QS

PQS = 5x

RQS = 2x + 6

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

PQS = RQS

Substitute expressions for PQS and RQS

5x = 2x + 6

Collect Like Terms

5x - 2x = 6

3x = 6

Divide both sides by 3

x = 2

Solving for PQR;

PQR = PQS + RQS

PQR = 5x + 2x + 6

PQR = 7x + 6

Substitute 2 for x

PQR = 7 * 2 + 6

PQR = 14 + 6

PQR = 20

4 0
3 years ago
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