Answer:
Step-by-step explanation:
Remark
The diagram is a mess of lines; you have to guess where that 12 belongs. Just to make the question a bit more interesting, I'm going to say the 12 belongs to the perpendicular.
If that's true you can find KT using Pythagorus. KT and RT are equal. (SSS)
So, let's go.
Givens
1/2 of ST = 1/2 32 = 16
12 is the leg of the small triangle KT and the third point where the perpenduclar line meets ST.
Solution
KT^2 = 16^2 + 12^2
KT^2 = 256 + 144
KT^2 = 400
KT = sqrt(400)
KT = 20
RK = KT because parts of a congruent triangle = parts of the other triangle containing the line (KT) that you are trying to find the length of.
Answer:
- Circle X with radius 2 cm.
- Either of two lines parallel to AB.
Step-by-step explanation:
1. The definition of a circle is all the points in a plane that are at some radius r from a given point (the circle center). That is what you have, with a radius of 2 cm.
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2. Parallel lines are the same distance apart everywhere. Each line will have two parallel lines at some given distance from it, one on each side. Here, the separation distance from AB is 1 cm, so your locus of points is the two lines parallel AB that are 1 cm from it on either side.
Answer:
1 hour
Step-by-step explanation:
Each graph shown lasts for 1/2 hour / 30 minutes
Answer:
if i can be brainliest that would be great
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
