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4 years ago

Help me please and thank you

Mathematics

2 answers:

Svetllana [295]4 years ago

7 0

When he has 8 postcards he spends 2 days on vacation because 4 multiplied by 2 is 8 and since there are 8 postcards it will be equal. So he will spends 2 days on vacation.

kap26 [50]4 years ago

4 0

Answer:

I this correct 2p = 8d, is this correct share your experience in the comment section????!!!

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An astronaut who weighs 95 kilograms on Earth weighs 15.8 kilograms on the Moon. How much would a person weigh on the Moon if th

shutvik [7]

I do not know but u should pay more respect

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3 years ago

About 50 percent of the math questions are multiple choice and 50 percent are grid-in.

OleMash [197]

The answer I think is false

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3 years ago

Read 2 more answers

What is the correct symbol?

Nadusha1986 [10]

Answer:

Since 10/9 is greater than 1, multiplying by 10/9 makes the value larger

Step-by-step explanation:

Step 1: Solve the fraction

10/9 = 1.1112

Therefore 10/9 > 1

Step 2: Multiple the fraction by itself

10/9 x 10/9 = 100/81

Convert fraction to decimals

100/81 = 1.2345678901.....

1.234567901 > 1.1112

Therefore 10/9 x 10/9 is bigger than 10/9

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4 years ago

A box of cereal states that there are 93 calories in a three fourths

cupoosta [38]

93/3 = 31, 31 x 4= 124

Calories per cup is 124

There are 372 calories in three cups

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4 years ago

Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac

uranmaximum [27]

One way to do this is to notice

$\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4$

Then

$\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}$

We have

$\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

and since $\tan x$ has a period of $\pi$ ,

$\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1$

and so

$\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3$

7 0

4 years ago