Your answer is
How do you solve 15+b=23
1 answer:
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<u>Given</u>:
The exterior angle P is 74°
The measure of ∠PRQ is 51°
We need to determine the measure of ∠PQR
<u>Measure of ∠QPR:</u>
From the figure, it is obvious that P is the intersection of the two lines.
The angle 74° and ∠QPR are vertically opposite angles.
Since, vertically opposite angles are always equal, then the measure of ∠QPR is 74°
Thus, the measure of ∠QPR is 74°
<u>Measure of ∠PQR:</u>
The measure of ∠PQR can be determined using the triangle sum property.
Thus, we have;
Substituting the values, we get;
Thus, the measure of ∠PQR is 55°
Hence, Option B is the correct answer.
Answer:
Depth of the submarine = 668.09 feet
Step-by-step explanation:
From the figure attached,
In triangle ABC,
Distance between a navy cruiser and a nuclear submarine = 2500 feet
Angle between the water level and the submarine = 15.5°
By applying sine rule in the given triangle,
sin(∠BAC)° =
sin(15.5°) =
BC = 2500[sin(15.5)]
BC = 668.09 feet
Therefore, submarine is 668.09 feet deep in the sea.
