Divide 336 by 2 then you will have the cost of 1in width and 3 in long then triple it which gets you 3in wide and 6 in long
Answer:18
Step-by-step explanation:6+8+4 =
18
Answer:
a. 2401.06
b. 37.54%
c. 56.3%
Step-by-step explanation:
hopefully this is right
*note: I think you forgot to convert 4-2 back into yards.
a. Robbie's field of view to the North end includes parts not on the football field. so to find the area of the football field he can see, we need to find:
total area of what Robbie sees - area of non football field Robbie sees
what you shaded represents the total of what Robbie sees. it's a triangle. area of a triangle is 1/2(b)(h) where h is distance away and b is width of view.
total area = 1/2(170)(30.92) = 2628.56 yd
area of non football field (pipe to South end)
= 1/2(50)(9.1) = 227.5
so 2628.56 - 227.5 = 2401.06
b. area found in part a / total area of football field
2401.06 / (120*53.3) = .3754
.3754 * 100 = 37.54%
c. the chance of Robbie seeing the touchdown depends on how much of the (North) endzone he can see.
area of north endzone is
10 * 53.3 = 533.
area Robbie sees in endzone is
2628.56 - 2328.48 = 300.08
(found by total area Robbie sees - area of non endzone Robbie sees)
300.08 / 533 = 0.563
= 56.3%
<em><u>Question:</u></em>
The sum of first n terms of an AP is given by Sn= 2n square +3n. Find the sixteenth term of the AP
<em><u>Answer:</u></em>
16th term of AP is 65
<em><u>Solution:</u></em>
Given that,
<em><u>The sum of first n terms of AP is given by:</u></em>
Let nth term in AP be:
<em><u>Then the nth term is given as:</u></em>
Where, from given,
<em><u>Thus nth term is given as:</u></em>
<em><u>To find the 16th term, substitute n = 16</u></em>
Thus 16th term of AP is 65