Question

PLEASE HELP ME.

Answer 1

Answer:

b.(-2, -1), (3, 4)

Step-by-step explanation:

We are given function as

$f(x)=x^4-3x^3-2x^2+3x-5$

We can verify each intervals

At (-6,-5):

Firstly we will plug x=-6

$f(-6)=(-6)^4-3(-6)^3-2(-6)^2+3(-6)-5=1849$

now, we can plug x=-5

$f(-5)=(-5)^4-3(-5)^3-2(-5)^2+3(-5)-5=930$

since, both are positive values

So, zeros can not lie between them

At (-4,-3):

Firstly we will plug x=-4

$f(-4)=(-4)^4-3(-4)^3-2(-4)^2+3(-4)-5=399$

now, we can plug x=-3

$f(-3)=(-3)^4-3(-3)^3-2(-3)^2+3(-3)-5=130$

since, both are positive values

So, zeros can not lie between them

At (-2,-1):

Firstly we will plug x=-2

$f(-2)=(-2)^4-3(-2)^3-2(-2)^2+3(-2)-5=21$

now, we can plug x=-1

$f(-1)=(-1)^4-3(-1)^3-2(-1)^2+3(-1)-5=-6$

since, one is positive and another is negative

So, zeros will lie between them

At (3,4):

Firstly we will plug x=3

$f(3)=(3)^4-3(3)^3-2(3)^2+3(3)-5=-14$

now, we can plug x=4

$f(4)=(4)^4-3(4)^3-2(4)^2+3(4)-5=39$

since, one is positive and another is negative

So, zeros will lie between them

zeros will be between

(-2, -1), (3, 4)

Answer 2

Answer:

its b

Step-by-step explanation: