<u>Answer:</u>
<u>For a:</u> Yes, he has gained weight.
<u>For b:</u> The number of onions required is 1.
<u>Explanation:</u>
We are given:
Weight of Brandon checked earlier = 183 lb
Converting this into kilograms, we use the conversion factor:
1 kg = 2.205 lb
So, 
And, weight of Brandon measured at the health club = 85.0 kg
As, the weight at the health club is more than the previous measured weight. So, Brandon has gained weight.
We are given:
Amount of diced onions a recipe calls = 125 g
Mass of 1 onion = 4 oz
Converting the mass of 1 onion to ounces, we use the conversion factor:
1 oz = 28.35 g
So, 
To calculate the number of onions, we use the equation:


Hence, the number of onions required is 1.
Answer:
Double and triple covalent bonds occur when four or six electrons are shared between two atoms, and they are indicated in Lewis structures by drawing two or three lines connecting one atom to another
Explanation:
The equation to be used are:
PM = ρRT
PV = nRT
where
P is pressure, M is molar mass, ρ is density, R is universal gas constant (8.314 J/mol·K), T is absolute temperature, V is volume and n is number of moles
The density of air at 23.5°C, from literature, is 1.19035 kg/m³. Its molar mass is 0.029 kg/mol.
PM = ρRT
P(0.029 kg/mol) = (1.19035 kg/m³)(8.314 J/mol·K)(23.5+273 K)
P = 101,183.9 Pa
n = 0.587 g * 1 kg/1000 g * 1 mol/0.029 kg = 0.02024 mol
(101,183.9 Pa)V = (0.02024 mol)(8.314 J/mol·K)(23.5+273 K)
Solving for V,
V = 4.931×10⁻⁴ m³
Since 1 m³ = 1000 L
V = 4.931×10⁻⁴ m³ * 1000
V = 0.493 L
Answer: 
Explanation:
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and are present in an aqueous state and represented in the form of ions.
Net ionic equation : In the net ionic equations, we do not not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The complete balanced ionic equation will be:
In this equation,
are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be:
