Percent strength (% w/w) of a solution is defined as the amount of solute present in 100 g of the solution.
Given data:
Mass of the solute, potassium chloride = 62.5 g
Volume of water (solution) = 187.5 ml
We know that the density of water = 1 g/ml
Therefore, the mass corresponding to the given volume of water
= 187.5 ml * 1 g/1 ml = 187.5 g
We have a solution of 62.5 g of potassium chloride in 187.5 g water
Therefore, amount of solute in 100 g of water= 62.5 * 100/187.5 = 33.33
The percentage strength = 33.33 %
The balanced dissociation equation for Cs₂CO₃ is:
Cs₂CO₃(aq) —> Cs⁺(aq) + CO₃²¯(aq)
A dissociation equation is an equation showing the available ions present in a solution.
To obtain the dissociation equation, the compound must be dissolved in water to produce an aqueous solution.
The dissociation equation for Cs₂CO₃ can be written as follow
Cs₂CO₃(aq) —> Cs⁺(aq) + CO₃²¯(aq)
Learn more about dissociation equation: brainly.com/question/1903354
Answer:
98.6 g/mol.
Explanation:
Equation of the reaction
HX + NaOH--> NaX + H2O
Number of moles = molar concentration × volume
= 0.095 × 0.03
= 0.00285 moles
By stoichiometry, 1 mole of HX reacted with 1 mole of NaOH. Therefore, number of moles of HX = 0.00285 moles.
Molar mass = mass ÷ number of moles
= 0.281 ÷ 0.00285
= 98.6 g/mol.
