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laila [671]
3 years ago
11

What is the sum of 0.0421 g + 5.263 g +2.13 g to the

Chemistry
1 answer:
myrzilka [38]3 years ago
4 0

Answer: D

Explanation:

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A sample of gas contains 0.1900 mol of CO(g) and 0.1900 mol of NO(g) and occupies a volume of 22.0 L. The following reaction tak
worty [1.4K]

Answer:

V₂ = 16.5 L

Explanation:

To solve this problem we use <em>Avogadro's law, </em>which applies when temperature and pressure remain constant:

V₁/n₁ = V₂/n₂

In this case, V₁ is 22.0 L, n₁ is [mol CO + mol NO], V₂ is our unknown, and n₂ is [mol CO₂ + mol N₂].

  • n₁ = mol CO + mol NO = 0.1900 + 0.1900 = 0.3800 mol

<em>We use the reaction to calculate n₂</em>:

2CO(g) + 2NO(g) → 2CO₂(g) + N₂(g)

  • mol CO₂:

0.1900 mol CO * \frac{2molCO_{2}}{2molCO} = 0.1900 mol CO₂

  • mol N₂:

0.1900 mol NO * \frac{1molN_{2}}{2molNO} = 0.095 mol N₂

  • n₂ = mol CO₂ + mol N₂ = 0.1900 + 0.095 = 0.2850 mol

Calculating V₂:

22.0 L / 0.3800 mol = V₂ / 0.2850 mol

V₂ = 16.5 L

3 0
3 years ago
Suppose the concentration of the standard stock solution is 50.04 ppm and that you delivered 4.60 mL of this standard stock solu
12345 [234]

Answer:

9.21 ppm

Explanation:

Considering

concentration_{working\ solution}\times Volume_{working\ solution}=concentration_{stock\ solution}\times Volume_{stock\ solution}

Given  that:

concentration_{working\ solution}=?

Volume_{working\ solution}=25.00mL

Volume_{stock\ solution}=4.60mL

concentration_{stock\ solution}=50.04 ppm

So,  

concentration_{working\ solution}\times 25.00mL=50.04 ppm\times 4.60mL

concentration_{working\ solution}=\frac{50.04\times 4.60}{25.00}\ ppm=9.21\ ppm

4 0
2 years ago
How many molecules are there in 100 g of glucose?
agasfer [191]
There are 0.55 moles in glucose
8 0
3 years ago
Which of the following is the best description of a conversion table
kirill [66]
Can’t tell ya bc you didn’t list the answers
3 0
2 years ago
Please help. Thank you:)
bearhunter [10]
These are guesses because there is no word bank or anything

A. Water
B. Housing
C. Plants
D. Animals
E. Warmth
5 0
3 years ago
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