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konstantin123 [22]
3 years ago
11

Y-3=? Help please!! Thank you!

Mathematics
2 answers:
nydimaria [60]3 years ago
5 0
It's just y-3 because they aren't like terms if you're talking about algebra.

This question was brief so I'm not sure what you're a skin but this is the algebra answer.
mario62 [17]3 years ago
4 0

Answer:

\mathrm{Axis\:interception\:points\:of}\:Y-3:\quad \mathrm{X\:Intercepts}:\:\left(3,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-3\right)

Step-by-step explanation:

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Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant
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The chain rule states that

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

Since \ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2), you have

\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}
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and

\dfrac{\mathrm dx}{\mathrm dt}=\cos t
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Also, since x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t, the derivative is

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