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inna [77]
3 years ago
9

You use 4 gallons of water on 14 plants in your graden. At this rate, how much water will it take to water 35 plants

Mathematics
1 answer:
Jlenok [28]3 years ago
8 0

It will take 10 gallons of water to water the 35 plants

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What is (4ab^0c^9)^3 ?​
fomenos

Answer:

  64a³c²⁷

Step-by-step explanation:

The expression inside parentheses can be simplified by noting that b^0 = 1. Then you have ...

  (4ac^9)^3

The rules of exponents say the exponent outside applies to each of the inside factors. For c^9, the exponents multiply.

Here are the applicable rules:

  (ab)^c = (a^c)(b^c)

  (a^b)^c = a^(b·c)

__

  (4ac^9)^3 = 4^3·a^3·c^(9·3) = 64a^3c^27

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3 years ago
-7=-x <br><br> One step equations ( Find X)
Marysya12 [62]

Answer:

answer of your question is

-x= -7

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3 years ago
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There are 6 muffins in a package.How many packages will be needed to feed 48 people if each person has 2 muffins?
Paladinen [302]
16 packages would be needed



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For f(x) =4x+1 g(x)=x²-5, find (f•g)(x)​
Inessa05 [86]

Answer:

(f · g)(x) = 4x³ + x² - 20x - 5

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property

<u>Algebra I</u>

  • Combining Like Terms
  • Expand by FOIL (First Outside Inside Last)

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 4x + 1

g(x) = x² - 5

(f · g)(x) is f(x)g(x)

<u>Step 2: Find (f · g)(x)</u>

  1. Substitute:                    (f · g)(x) = (4x + 1)(x² - 5)
  2. Expand [FOIL]:             (f · g)(x) = 4x³ - 20x + x² - 5
  3. Combine like terms:    (f · g)(x) = 4x³ + x² - 20x - 5
3 0
3 years ago
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A projectile is fired at such an angle that the vertical
svetoff [14.1K]

(a) The projectile remains in the air for 10 seconds

(b) It travels a horizontal distance of 600 meters

Step-by-step explanation:

A projectile is fired at such an angle that

1. The vertical  component of its velocity is 49 m/sec

2. The horizontal  component of its velocity is 60 m/sec

We need to find:

(a) How long the projectile remains in the air

(b) The horizontal distance it travels

∵ The vertical distance y = u_{y} t - \frac{1}{2} g t², where

u_{y} is the vertical  component of its velocity, g is the acceleration

of gravity and t is the time

∵ y = 0 ⇒ it return to the same initial height

∵ u_{y} = 49 m/s

∵ g = 9.8 m/s²

- Substitute these values in the rule above

∴ 0 = 49 t - \frac{1}{2} (9.8) t²

∴ 0 = 49 t - 4.9 t²

- Take t as a common factor

∴ 0 = t (49 - 4.9 t)

- Equate each term by 0

∴ t = 0 ⇒ at initial position

∴ 49 - 4.9 t = 0

- Add 4.9 t to both side

∴ 49 = 4.9 t

- Divide both sides by 4.9

∴ t = 10 seconds

(a) The projectile remains in the air for 10 seconds

∵ The horizontal distance = u_{x} t, where u_{x} is the

   horizontal component of its velocity

∵ u_{x} = 60 m/sec

∵ t = 10 seconds

∴ x = 60 × 10 = 600 meters

(b) It travels a horizontal distance of 600 meters

Learn more:

You can learn more about the component of velocity in brainly.com/question/4464845

#LearnwithBrainly

3 0
3 years ago
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