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3 years ago

Quick math graph question. Multiple choice. Please help.

Mathematics

1 answer:

Brrunno [24]3 years ago

4 0

Answer:

first one

Step-by-step explanation:

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Zack, Jack and Sasha earned £250 altogether delivering leaflets.

AleksAgata [21]

Answer:

Zack earned £125, Jack earned £75, and Sasha earned £50

Step-by-step explanation:

Considering the number of leaflets delivered

Zack 50%, Jack 30% and Sasha 20%

Total delivered = 50 + 30 + 20 = 100%

If they earn £250 on the 100% delivery, then each will have as shown below

Zack = (50/100)*250

= 5*25

= £125

Jack = (30/100)*250

= 3*25

= £75

Sasha = (20/100)*250

=2*25

= £50

5 0

4 years ago

Read 2 more answers

Circle X with a radius of 6 units and circle Y with a radius of 2 units are shown.

Natali [406]

Answer:

Translate the circles so they share a common center point, and dilate circle Y by a scale factor of 3.

Step-by-step explanation:

5 0

4 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago

What is the measure of <4 if the measure of <1 = 110°?

goblinko [34]

Answer:

look at the picture i have sent

8 0

3 years ago

3a2+4b for a=2 and b=3

Kobotan [32]

First you’ll multiply to get 3x2x2 + 4x3. Then add them together. 12+12=24

4 0

3 years ago