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STatiana [176]
3 years ago
15

Which products result in a difference of of squares? check all that apply.

Mathematics
1 answer:
igomit [66]3 years ago
6 0

Answer:

B, D

Step-by-step explanation:

The product of a sum and a difference results in a difference of squares.

The product must be of the form (a + b)(a - b) to work.

Answer: B, D

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Please help need to turn in almost ! Pic below<br> Thank you so much:)
11111nata11111 [884]

Answer:

x = 90-73

= 17°

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4 0
3 years ago
Read 2 more answers
What is the property of 22•1-22?
quester [9]

Answer:

here according to BODMAS

we first have to multiply then subtract

so 22×1=22

then 22-22=0

4 0
3 years ago
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A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h
Tanya [424]

Answer:

  192 cm^3/min

Step-by-step explanation:

Differentiating the volume expression, we get ...

  dV/dt = 2xh(dx/dt) +x^2(dh/dt)

We are given that ...

  x = 4 cm, dx/dt = 2 cm/min, h = 15 cm, dh/dt = -3 cm/min

Putting these values into the formula for volume rate of change, we get ...

  dV/dt = 2(4 cm)(15 cm)(2 cm/min) +(4 cm)^2(-3 cm/min)

  = 240 cm^3/min -48 cm^3/min

  dV/dt = 192 cm^3/min

8 0
3 years ago
If t varies inversely as a and t= 2 when a = -4, what is t when a = 1/3?
bezimeni [28]

Answer:

t = - 24

Step-by-step explanation:

Given t varies inversely as a then the equation relating them is

t = \frac{k}{a} ← k is the constant of variation

To find k use the condition t = 2 when a = - 4

2 = \frac{k}{-4} ( multiply both sides by - 4 )

- 8 = k

t = \frac{-8}{a} ← equation of variation

When a = \frac{1}{3} , then

t = \frac{-8}{\frac{1}{3} } = - 24

5 0
3 years ago
A chip used in the production of particleboard (Question 4) has a 15% chance of containing excessive bark. What is the probabili
salantis [7]

Answer:

0.2

Step-by-step explanation:

Given that:

P(particleboard with excessive bark) = 0.15

The P(that particleboard do not have excessive bark) = 1 - 0.15

i.e the population proportion number of success p = 0.85

The sample size (n) is given to be = 1000

To find the P(X ≥ 860)

Since the sample size is large, we will apply the normal approximation of binomial distribution to treat this question.

The population mean \mu = n \times p

\mu = 1000 \times 0.85

\mu =850

The population standard deviation \sigma = \sqrt{n*p(1-p)

\sigma = \sqrt{1000*0.85*(1-0.85)}

\sigma = \sqrt{1000*0.85*(0.15)}

\sigma = \sqrt{127.5}

\sigma = 11.2916

Let X be the random variable which obeys a normal distribution;

Then;

P(X \ge 860) = P(Z\ge \dfrac{x- \mu}{\sigma})

P(X \ge 860) = P(Z\ge \dfrac{860- 850}{11.2916})

P(X \ge 860) = P(Z\ge \dfrac{10}{11.2916})

P(X ≥ 860) = P(Z ≥ 0.8856)

P(X ≥ 860) = 1 - P(Z ≤ 0.8856)

From  z table

P(X ≥ 860) = 1 - 0.8122

P(X ≥ 860) = 0.1878

P(X ≥ 860) \simeq 0.2

Thus, the probability of having more than 860 bark-free chips in a batch of 1,000 = 0.2

6 0
3 years ago
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