Answer:
here according to BODMAS
we first have to multiply then subtract
so 22×1=22
then 22-22=0
Answer:
192 cm^3/min
Step-by-step explanation:
Differentiating the volume expression, we get ...
dV/dt = 2xh(dx/dt) +x^2(dh/dt)
We are given that ...
x = 4 cm, dx/dt = 2 cm/min, h = 15 cm, dh/dt = -3 cm/min
Putting these values into the formula for volume rate of change, we get ...
dV/dt = 2(4 cm)(15 cm)(2 cm/min) +(4 cm)^2(-3 cm/min)
= 240 cm^3/min -48 cm^3/min
dV/dt = 192 cm^3/min
Answer:
t = - 24
Step-by-step explanation:
Given t varies inversely as a then the equation relating them is
t =
← k is the constant of variation
To find k use the condition t = 2 when a = - 4
2 =
( multiply both sides by - 4 )
- 8 = k
t =
← equation of variation
When a =
, then
t =
= - 24
Answer:
0.2
Step-by-step explanation:
Given that:
P(particleboard with excessive bark) = 0.15
The P(that particleboard do not have excessive bark) = 1 - 0.15
i.e the population proportion number of success p = 0.85
The sample size (n) is given to be = 1000
To find the P(X ≥ 860)
Since the sample size is large, we will apply the normal approximation of binomial distribution to treat this question.
The population mean 


The population standard deviation 




Let X be the random variable which obeys a normal distribution;
Then;



P(X ≥ 860) = P(Z ≥ 0.8856)
P(X ≥ 860) = 1 - P(Z ≤ 0.8856)
From z table
P(X ≥ 860) = 1 - 0.8122
P(X ≥ 860) = 0.1878
P(X ≥ 860)
0.2
Thus, the probability of having more than 860 bark-free chips in a batch of 1,000 = 0.2