How would I write 21/8 as a mixed number?

2 answers:

3 0

Divide 21 by 8. and then whatever the reminder comes will go as the whole number
and the reminder will be the numerator and the number 8 will be the denominator.
the answer is 2 5/8
2 is the whole number, 5 is the numerator and 8 is the denominator

natka813 [3]3 years ago

3 0

21
8
=21÷8
quotient=2 and remainder=5.So quotient will be whole number and remainder will be numerator.Also 8 will be the denominator.
21=2 5
8 8

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How do I solve this????

Arlecino [84]

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4 more than "that", will be "that" + 4
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so.. whatever "a" is, "b" is 5a+4

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so $\bf \begin{cases}
a+b=22\\
--------------\\
\boxed{b}=5a+4\qquad thus\\
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masha68 [24]

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2 years ago

Read 2 more answers

Solve y=f(x) for x. Then find the input when the output is -3.

DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(x-5\right)^3-1$

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

$\:\:y=\:\left(x-5\right)^3-1$

$-3\:=\:\left(x-5\right)^3-1\:\:\:$

switch sides

$\left(x-5\right)^3-1=-3$

Add 1 to both sides

$\left(x-5\right)^3-1+1=-3+1$

$\left(x-5\right)^3=-2$

$\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

Thus, the input values are:

$x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}$