The answer is 30.
First off, the numbers are consecutive even numbers. So, the difference between every consecutive number is 2 (numbers go from even to odd to even to odd...). Since the sum of their numbers is 96, I divided that by 3 to get 32. This gives me the median of the three numbers. To find the smallest number, I simply subtracted 2 from the 32.
This may help:
96/3=32
32 + 32 + 32 = 96
(32-2)+(32+0)+(32+2)=96
30+32+34=93
P^8 • p^−3 • p^2<span>=<span><span>p^10/</span><span>p^3</span></span></span><span>=<span>p7
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Answer:
<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>
Step-by-step explanation:
Givens
- Max has $5.50.
- He has eight more quarters than he does nickels.
- He had four times as many dimes as he has nickels.
From these statements, we can deduce algebraical expressions to solve the problem. Let's call
quarters,
nickels and
dimes.
(8 more quarters than nickels)
(he has four times as many dimes as he has nickels).
(Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).
Let's replace the first two expressions into the third equation

There are 5 nickels.
Now, we use this value to find the number of quarters

There are 13 quarters.
Also, 
There are 20 dimes.
Therefore, there are 13 quarters, 5 nickels and 20 dimes.
We have to start by creating an equation.
Cost of System = x
Cost of games = 3x
Thus x + 3x = $500
Now we find x.
4x = 500,
x = 500/4 = 125
So the system is 125,
The games, 125*3 = 375