1> distributed
10x - 40 = 20
2 > move - 40 -- + 40
10x = 20 + 40
10x = 60
3 > divide 10
x = 6
STEP 1:
Divide the length of the ribbon by the size of the pieces.
12 inches= 1 foot
= 9 ft ÷ 15 inch pieces
convert ft to inches
= (12)(9) ÷ 15
= 108 ÷ 15
= 7.2 pieces from one roll
STEP 2:
multiply the number of pieces that can be cut from one roll by the number of rolls
= 7.2 pieces * 5 rolls
= 36 pieces total from 5 rolls
ANSWER: The greatest number of 15-inch pieces that can be cut from five 9-foot rolls is 36.
Hope this helps! :)
Answer:
the answer to the question is answer C
Step-by-step explanation:
The answer is dhdt=325πmmin.
With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:
V=πr2h
There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:
V=π(5m)2h
Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:
dVdt=(25m2)πdhdt
In the problem, we are given 3m3min which is dVdt. So we substitute this in:
dhdt=3m3min(25m2)π=325πmmin
Answer:
180 m
Step-by-step explanation: