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3 years ago

Part A: solve -np - 70 < 40 for n show your work

1 answer:

8 0

Step 1. Add 70 to both sides

$-np\ \textless \ 40+70$

Step 2. Simplify 40 + 70 to 110

$-np\ \textless \ 110$

Step 3. Divide both sides by $p$

$-n\ \textless \ \frac{110}{p}$

Step 4. Multiply both sides by $-1$

$n\ \textgreater \ - \frac{110}{p}$

Done! :)

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Dylan has a bank that sorts coins as they are dropped into it. A panel on the front displays the total number of coins inside as

vesna_86 [32]

Answer:

1). System of equations- D + Q = 90 and D + 2.5Q = 175.50

2). There are 33 dimes and 57 quarters in the bank.

Step-by-step explanation:

Dylan has a bank that sorts coins as they are dropped in it.

A panel shows the total number of coins inside as well as the total value of these coins.

Let the number of dimes in the bank = D

and the number of quarters in the bank = Q

If the panel shows total number of coins = 90

Then the equation will be

D + Q = 90 -------(1)

And the panel displays the amount of the coins = $17.55

Then equation will be

0.10D + 0.25Q = 17.55 [1 Dime = $0.10 and 1 quarter = $0.25]

D + 2.5Q = 175.50 ------------(2)

Now we subtract equation (1) form equation (2)

D + 2.5Q - (D + Q) = 175.50 - 90

D + 2.5Q - D - Q = 85.5

1.5Q = 85.5

Q = $\frac{85.5}{1.5}$

= 57

By putting Q = 57 in the equation (1)

D + 57 = 90

D = 90 - 57 = 33

Therefore, there are 33 dimes and 57 quarters in the bank.

4 0

3 years ago

Solve 5 divided by 2 5/7

solmaris [256]

Answer:

$\large\boxed{1\dfrac{16}{19}}$

Step-by-step explanation:

$5\div2\dfrac{5}{7}\qquad\text{convert the mixed number to improper fraction}\\\\2\dfrac{5}{7}=\dfrac{2\cdot7+5}{7}=\dfrac{19}{7}\\\\=5\div\dfrac{19}{7}=5\cdot\dfrac{7}{19}=\dfrac{(5)(7)}{19}=\dfrac{35}{19}=1\dfrac{16}{19}$

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svetoff [14.1K]

Answer:

I have solved on my own.

contains the answer to your question.

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3 years ago

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A simple random sample of size has mean and standard deviation.Construct a confidence interval for the population mean.The param

scZoUnD [109]

ANSWER:

EXPLANATION:

A simple random sample of size has mean and standard deviation. Construct a confidence interval for the population mean. The parameter is the population The correct method to find the confidence interval is the method.

The sample size is not given. Mean and Standard Deviation are not given.

To construct a confidence interval for the population mean, first find out the margin of error of the sample mean. This is why you need a confidence interval. If you are 90% confident that the population mean lies somewhere around the sample mean then you construct a 90% confidence interval.

This is equivalent to an alpha level of 0.10

If you are 95% sure that the population mean lies somewhere around the sample mean, your alpha level will be 0.05

In summary, get the values for sample size (n), sample mean, and sample standard deviation.

Make use of a degrees of freedom of (n-1).

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