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3 years ago

Part A: solve -np - 70 < 40 for n show your work

1 answer:

8 0

Step 1. Add 70 to both sides

$-np\ \textless \ 40+70$

Step 2. Simplify 40 + 70 to 110

$-np\ \textless \ 110$

Step 3. Divide both sides by $p$

$-n\ \textless \ \frac{110}{p}$

Step 4. Multiply both sides by $-1$

$n\ \textgreater \ - \frac{110}{p}$

Done! :)

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Step-by-step explanation:

Given

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$m = 10,000 kg$ --- solid mass

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Required

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Next, calculate the amount of solid left.

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