x= r - h/y subtract r from both sides
x-r = -h/y multiply each side by -y
-y(x-r) = h
-xy +yr = h
Answer:
1st option
Step-by-step explanation:
The domain and range are all real numbers , that is
domain { x | x ∈ R }
range { y | y ∈ R }
What is the interquartile range of this data set?<br>
2,5,9,11,18, 30, 42, 48, 55, 73, 81
Lubov Fominskaja [6]
Answer:
46
Step-by-step explanation:
55-9=46
2=min
9=Lq
30=median
55= Uq
81= max
The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)
The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)
Answer: The system of inequalities would produce the region indicated on the graph is Option B
Answer:
4,11,7,14,10,17,13,20,16,23,19,26........
