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2 years ago

What would be the total number of outcomes in each sample space?

Mathematics

1 answer:

Lerok [7]2 years ago

3 0

Answer:

810

Step-by-step explanation:

In this case the sample space would be the number of combinations that can be made with the numbers from 1 to 30 with the letters of the alphabet, from "a" to "z", for example:

A1, A22, C4, F9, etc

Now we know how many numbers are 30, now the alphabet has 27 letters, therefore, the number of combinations are:

27 * 30 = 810

Which means that the total number of results is 810.

You might be interested in

On a map, 2 inches represents an actual distance of 64 miles. Towns A and B are 608 miles apart. Find the distance between the t

Lelu [443]

Answer: The distance in the map is 19 inches.

Step-by-step explanation:

On the map. 2 inches represent an actual distance of 64 miles.

The actual distance between town A and town B is equal to 608 miles, we need to divide this distance into groups of 64 miles.

N = 608/64 = 9.5

And each one of those 9.5 groups is represented with 2 inches in the map, then the distance in the map is:

d = 9.5*2 inches = 19 inches.

6 0

3 years ago

Read 2 more answers

Are the two triangles below similar??

kodGreya [7K]

Answer:

Yes

Step-by-step explanation:

If you find the value of all the angles, you'll find that both triangles' angles are 50, 35, and 90 degrees.

(all the angles in a triangle add up to 180)

7 0

2 years ago

Your state is considering raising the legal age for consumption of alcoholic beverages to 21 years old. How large a sample size

julsineya [31]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.01}{2.58})^2}=16641$

And rounded up we have that n=16641

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$z_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.01$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

For this case we can use as estimator for the proportion $\hat p =0.5$ , since we don't have any other previous info. And replacing into equation (b) the values from part a we got: