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Leokris [45]
3 years ago
10

What numbers can i multiply to get -30

Mathematics
1 answer:
Finger [1]3 years ago
7 0

-1 X 30

1 X -30

-2 X 15

2 X -15

-3 X 10

3 X -10

-4 X 7.5

4 X -7.5

-5 X 6

5 X -6

Hope this helps! ;)

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Solve for x. 7 – 4x = 31 A. x = 6 B. x = 9.5 C. x = –6 D. x = –9.5
Eduardwww [97]

7-4x= 31

Bring over 7 to the other side

Positive 7 changes into negative 7

7-7-4x= 31-7

-4x= 24

Divide by -4 for -4x and 24

-4x/-4= 24/-4

x= -6

Check answer by using substitution method

7-4x= 31

7-4(-6)= 31

7+24= 31

31= 31

Answer : C. x= -6

5 0
3 years ago
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Please show the working and answer. you can take a picture for the working.
baherus [9]

Answer:

(a) The area of the triangle is approximately 39.0223 cm²

(b) ∠SQR is approximately 55.582°

Step-by-step explanation:

(a) By sin rule, we have;

SQ/(sin(∠SPQ)) = PQ/(sin(∠PSQ)), which gives;

5.4/(sin(52°)) = 6.8/(sin(∠PSQ))

∴ (sin(∠PSQ)) = (6.8/5.4) × (sin(52°)) ≈ 0.9923

∠PSQ = sin⁻¹(0.9923) ≈ 82.88976°

Similarly, we have;

5.4/(sin(52°)) = SP/(sin(180 - 52 - 82.88976))

Where, 180 - 52 - 82.88976 = ∠PQS = 45.11024

SP = 5.4/(sin(52°))×(sin(180 - 52 - 82.88976)) ≈ 4.8549

Given that RS : SP = 2 : 1, we have;

RS = 2 × SP = 2 × 4.8549 ≈ 9.7098

We have by cosine rule, \overline {RQ}² =  \overline {SQ}² +  \overline {SR}² - 2 × \overline {SQ} × \overline {SR} × cos(∠QSR)

∠QSR and ∠PSQ are supplementary angles, therefore;

∠QSR = 180° - ∠PSQ = 180° - 82.88976° = 97.11024°

∠QSR = 97.11024°

Therefore;

\overline {RQ}² =  5.4² +  9.7098² - 2 ×  5.4×9.7098× cos(97.11024)

\overline {RQ}² ≈ 136.42

\overline {RQ} = √(136.42) ≈ 11.6799

The area of the triangle = 1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

By substituting the values, we have;

1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

1/2 × 6.8 × (4.8549 + 9.7098) × sin(52°) ≈ 39.0223 cm²

The area of the triangle ≈ 39.0223 cm²

(b) By sin rule, we have;

\overline {RS}/(sin(∠SQR)) = \overline {RQ}/(sin(∠QSR))

By substituting, we have;

9.7098/(sin(∠SQR)) = 11.6799/(sin(97.11024))

sin(∠SQR) = 9.7098/(11.6799/(sin(97.11024))) ≈ 0.82493

∠SQR = sin⁻¹(0.82493) ≈ 55.582°.

8 0
3 years ago
Please help with this slope equation math problem! Thank you!!
Andru [333]

Answer:

I think it will be 2/1

Step-by-step explanation:

Its positive I know that, but since the points go right two and up one that should be the slope if i'm not mistaken.

8 0
3 years ago
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An easy question all wrong or unhelpful or no-work answers will be reported.
miss Akunina [59]
Elimination:

7x - 3y = 20
5x + 3y = 16
(add)
12x = 36
÷ 12
x = 3

(5 × 3) + 3y = 16
15 + 3y = 16
- 15
3y = 1
÷ 3
y = 1/3

Substitution:

5x + 3y = 16
- 3y
5x = 16 - 3y
÷ 5
x = 3.2 - 0.6y

5(3.2 - 0.6y) + 3y = 16
16 - 3y + 3y = 16
16  = 16
- 16
6y = 0
÷ 6
y = 0

Sorry the substitution messed up for some reason, I'll fix it after I've answered the other question

6 0
3 years ago
Turner mesuares 3/4 foot of a ribbon for a coustume. He needs 9 pieces of ribbon with the same length
AlekseyPX
That answer is 6.75
7 0
3 years ago
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