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3 years ago

A number cube is rolled 63 times. predict how many times the cube will land on a number that is a factor of 6 .

1 answer:

4 0

You said cube, so I assume a standard 6 sided die with numbers 1,2,3,4,5,6

how many times you said
we need to find how many fulfill the condition

how many numbers from 1,2,3,4,5,6 are a factor of 6?
1 is a factor
2 is a factor
3 is a factor
6 is a factor

so 4 numbers
there are 6 sides, so we would expect it to land of a factor of 6 a grand total of 4/6 or 2/3 times

so 2/3 of the time we will get a factor of 6

so find 2/3 of 63 to get number of times we get a factor of 6
2/3 of 63=2/3 times 63=42
so it will land about 42 times

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Dwayne buys a pumpkin that weighs 12.65 pounds.To the nearest tenth of a pound,how much dose the pumpkin weigh?

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12.60 is the answer.

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3 years ago

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3 years ago

1. Approximate the given quantity using a Taylor polynomial with n3.

Jet001 [13]

Answer:

See the explanation for the answer.

Step-by-step explanation:

Given function:

$f(x) = x^{1/4}$

The n-th order Taylor polynomial for function f with its center at a is:

$p_{n}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(n)}a}{n!} (x-a)^{n}$

As n = 3 So,

$p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{3!} (x-a)^{3}$

$p_{3}(x) = f(a) + f'(a) (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +...+\frac{f^{(3)}a}{6} (x-a)^{3}$

$p_{3}(x) = a^{1/4} + \frac{1}{4a^{ 3/4} } (x-a)+ (\frac{1}{2})(-\frac{3}{16a^{7/4} } ) (x-a)^{2} + (\frac{1}{6})(\frac{21}{64a^{11/4} } ) (x-a)^{3}$

$p_{3}(x) = 81^{1/4} + \frac{1}{4(81)^{ 3/4} } (x-81)+ (\frac{1}{2})(-\frac{3}{16(81)^{7/4} } ) (x-81)^{2} + (\frac{1}{6})(\frac{21}{64(81)^{11/4} } ) (x-81)^{3}$

$p_{3} (x)$ = 3 + 0.0092592593 (x - 81) + 1/2 ( - 0.000085733882) (x - 81)² + 1/6

(0.0000018522752) (x-81)³

$p_{3} (x)$ = 0.0092592593 x - 0.000042866941 (x - 81)² + 0.00000030871254

(x-81)³ + 2.25

Hence approximation at given quantity i.e.

x = 94

Putting x = 94

$p_{3} (94)$ = 0.0092592593 (94) - 0.000042866941 (94 - 81)² +

0.00000030871254 (94-81)³ + 2.25

= 0.87037 03742 - 0.000042866941 (13)² + 0.00000030871254(13)³ +

2.25

= 0.87037 03742 - 0.000042866941 (169) +

0.00000030871254(2197) + 2.25

= 0.87037 03742 - 0.007244513029 + 0.0006782414503 + 2.25

$p_{3} (94)$ = 3.113804102621

Compute the absolute error in the approximation assuming the exact value is given by a calculator.

Compute $\sqrt[4]{94}$ as $94^{1/4}$ using calculator

Exact value:

$E_{a}$ (94) = 3.113737258478

Compute absolute error:

Err = | 3.113804102621 - 3.113737258478 |

Err (94) = 0.000066844143

If you round off the values then you get error as:

|3.11380 - 3.113737| = 0.000063

Err (94) = 0.000063

If you round off the values up to 4 decimal places then you get error as:

|3.1138 - 3.1137| = 0.0001

Err (94) = 0.0001

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4 years ago

At the henning poultry farm, 56 of he 280 chickens being raised are Leghorn chickens. What is the ratio of the number of Leghorn

Virty [35]

1:5 56/280 is .2 which can be converted to 1/5 which is the same in ratio form.

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4 years ago

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Find dy du , du dx , and dy dx .

dangina [55]

Answer:

a) $\frac{dy}{du}=5(x^2 +1)^4$ , $\frac{du}{dx}=2x$ , $\frac{dy}{dx}=10x(x^2+1)^4$

b) $\frac{dy}{du}=4(4x^2-x+6)^3$ , $\frac{du}{dx}=8x-1$ , $\frac{dy}{dx}=4(8x-1)(4x^2-2+6)^3$

Step-by-step explanation:

We can use the chain rule in the following form: is u=u(x) is a differentiable function depending on x and y=y(u) is a differentiable function depending on u, then $\frac{dy}{dx}=\frac{dy}{du} \frac{du}{dx}$ .