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exis [7]
3 years ago
14

A central angle θ in a circle with a radius of 6.4 centimeters intercepts an arc with a length of 8 centimeters. What is the rad

ian measure of θ ? Enter your answer, as a decimal, in the box.
Mathematics
1 answer:
vlada-n [284]3 years ago
7 0
Radius of the circle = r = 6.4 cm
Length of the arc = s = 8 cm
Measure of angle formed by the arc = <span>θ = ?

The radius of the circle, arc length and the angle made by the arc at the center of the circle are related by the equation:

s = r</span><span>θ

From here we can find </span><span>θ by:

</span><span>θ = s/r

Using the values, we get:

</span><span>θ = 8/6.4
</span><span>
θ</span><span>= 1.25 radians

Thus the radian measure of the angle </span>θ made by the arc will be 1.25 radians
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\Large \text {Answer:}

\large \boxed {\dfrac{23}{40}}

\Large \text {Step-by-step explanation:}

\text{P}_{B}(r) = \text{P}_{A}(r) \cdot \text{P}_{B}(r) + \text{P}_{A}(w) \cdot \text{P}_{B}(r)

\text{P}_{B}(r) = \left (\dfrac{3}{5} \right ) \negthickspace \left(\dfrac{5}{8}\right ) + \left (\dfrac{2}{5} \right ) \negthickspace \left (\dfrac{4}{8} \right )

\text{P}_{B}(r) = \dfrac{23}{40}

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Answer:

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Step-by-step explanation:

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