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kozerog [31]
3 years ago
6

How to use 22/7 for pi

Mathematics
1 answer:
V125BC [204]3 years ago
3 0
Your teacher just wants you to replace pi any equations with 22/7 because it is close to pi
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Solve using the quadratic formula. Select the correct solution.<br> -7x=2x^2+9
gayaneshka [121]

The answer to your question is B!

Have a wonderful day.

7 0
3 years ago
Describe the motion of a particle with position (x, y) as t varies in the given interval. (For each answer, enter an ordered pai
DerKrebs [107]

Answer:

The motion of the particle describes an ellipse.

Step-by-step explanation:

The characteristics of the motion of the particle is derived by eliminating t in the parametric expressions. Since both expressions are based on trigonometric functions, we proceed to use the following trigonometric identity:

\cos^{2} t + \sin^{2} t = 1 (1)

Where:

\cos t = \frac{y-3}{2} (2)

\sin t = x - 1 (3)

By (2) and (3) in (1):

\left(\frac{y-3}{2} \right)^{2} + (x-1)^{2} = 1

\frac{(x-1)^{2}}{1}+\frac{(y-3)^{2}}{4} = 1 (4)

The motion of the particle describes an ellipse.

7 0
3 years ago
ANSWER QUICKLY PLEASE : Eight times the square root of a number is
mezya [45]

Answer:

I don't know what you're answer is supposed to look like but if you're creating an equation it should be this...

Step-by-step explanation:

( 4 · √x ) - ( 8 · √x )

3 0
2 years ago
Which exponential model best represents the data? O f(x) = 3(1.2) O f(x) = 2(0.3)* O f(x) = 2(3)* O f(x) = 3(0.2)*​
aleksley [76]

The exponential model has an initial value of 3

The exponential model of the data is f(x) = 3 * (1.2)^x

<h3>How to determine  the exponential model?</h3>

From the complete question,we have the following parameters:

  • Initial value, a = 3
  • Growth rate, r = 0.2

The exponential model is then calculated as:

f(x) = a * (1 + r)^x

Substitute known values

f(x) = 3 * (1 + 0.2)^x

Evaluate the sum

f(x) = 3 * (1.2)^x

Hence, the exponential model of the data is f(x) = 3 * (1.2)^x

Read more about exponential models at:

brainly.com/question/7296382

3 0
2 years ago
What is the sum or difference?
dlinn [17]
1. Ans: Option (B) -6x^4

Explanation:
Given: 2x^4 - 8x^4
Take the common out:
=> x^4(2 - 8)

Hence: => [tex]-6x^4[/tex] (Option B)

2. Ans: Option (D) -3y^5

Explanation:
Given: 6y^5 - 9y^5
Take the common term(s) out:
=> y^5(6-9)

Hence: => -3y^5 (Option D)

3. Ans: Option (B) 9x^2 - 12x + 6<span> quadratic trinomial 

Explanation:
</span>Given: 6 - 12x + 13x^2 - 4x^2

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> 
13x^2 - 4x^2 - 12x + 6
=> 9x^2 - 12x + 6 (Option B)

4. Ans: Option (C) 7.3x^2 + 0.8x + 1.3

Explanation:
In order to find the total number of C<span>ommon and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

</span>Common guppies: 3.1x^2 +6.0x + 0.3<span>
Endler's guppies:   </span>4.2x^2 - 5.2x + 1.0
(add both)
-----------------------------------------------------------------
Total number:          7.3x^2 +0.8x + 1.3
-----------------------------------------------------------------
Hence the ans is Option(C) 7.3x^2 + 0.8x + 1.3

5. Ans: Option (D) 2x^2(133 - 18 \pi )

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = 266x^2

Now the area of the circular fountain:
Area of the Circular Fountain = \pi r^2
Since, r=6x
Therefore,
Area of the Circular Fountain = \pi (6x)^2 = 36 \pi x^2

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = 266x^2 - 36 \pi x^2
=> Final area of the Yard = 2x^2(133 - 18 \pi) (Option D)

6. Ans: Option (A) 56x^2

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = 60x^2

Now the area of the stadium:
Area of the stadium = 1x * 4x = 4x^2

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= 60x^2 - 4x^2
=> Final area of the lot = 56x^2 (Option A)

-i
4 0
3 years ago
Read 2 more answers
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