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liraira [26]
4 years ago
11

Consider the relation {(−5, 8), (4, −2), (4, 1), (3, 0)} . What integer is in the domain?

Mathematics
1 answer:
Gre4nikov [31]4 years ago
6 0

<em><u>Question:</u></em>

Consider the relation {(−5, 8), (4, −2), (4, 1), (3, 0)} . What integer is in the domain?

A 8

B -2

C -5

D -1

<em><u>Answer:</u></em>

Option C

The domain is -5, 4, 4, 3

<em><u>Solution:</u></em>

Given relation is:

{(-5, 8), (4, -2), (4, 1), (3, 0)}

<em><u>Let us understand about domain and range</u></em>

Domain refers to the set of possible input values

Range is the set of possible output values

Thus the input values in given relation are:

(x, y) = (-5, 8) , (4, -2) , (4, 1) , (3, 0)

The input values are values of "x"

Input values = -5, 4, 4, 3

Thus the domain of given relation are -5, 4, 4, 3

Thus option C is correct

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Answer:

Part 1) c=12.14\ units

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Step-by-step explanation:

step 1

Find the measure of side c

Applying the law of cosines

c^2=a^2+b^2-2(a)(b)cos(C)

we have

a=9\ units\\b=13\ units\\C=64^o

substitute

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c=12.14\ units

step 2

Find the measure of angle A

Applying the law of sines

\frac{a}{sin(A)}=\frac{c}{sin(C)}

substitute the given values

\frac{9}{sin(A)}=\frac{12.14}{sin(64^o)}

solve for sin(A)

sin(A)=\frac{sin(64^o)}{12.14}(9)

sin(A)=0.6663

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step 3

Find the measure of angle B

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

m\angle A+m\angle B+m\angle C=180^o

substitute the given values

41.78^o+m\angle B+64^o=180^o

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m\angle B=180^o-105.78^o

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