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Makovka662 [10]

3 years ago

8

Calculate AC Round to the nearest tenth.

2 answers:

Alex17521 [72]3 years ago

8 0

Answer:

AC = 11.4

Step-by-step explanation:

6/sin 23 = AC/sin 132

6 sin 132/sin 23 = AC

AC = 11.4

Free_Kalibri [48]3 years ago

3 0

Answer:

3,266.53

Step-by-step explanation:

i looked it up :)

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0.01 meter or 1/100 meter equals one:

Stels [109]

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There are 100 centimeters in a meter, so if you would divide a meter by 100, you'd get 1 centimeter.

Answer: B.) Centimeter.
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5 0

3 years ago

Read 2 more answers

In this line of circles, the ratio of red circles to blue circles is 1:3 How many more circles would need to be added to make th

zaharov [31]

Answer:

The number of red circles to be added would be equal to 8 times the original amount of red circles

Step-by-step explanation:

Let

x ----> the number of red circles

y ----> the number of blue circles

Originally

$\frac{x}{y}=\frac{1}{3}$

$y=3x$ ----> equation A

How many more circles would need to be added to make the ratio of red to blue 3:1

Let

n ----> the number of additional red circles

$\frac{x+n}{y}=\frac{3}{1}$ ----> equation B

substitute equation A in equation B

$\frac{x+n}{3x}=\frac{3}{1}$

solve for n

$x+n=9x\\n=9x-x\\n=8x$

therefore

The number of red circles to be added would be equal to 8 times the original amount of red circles

5 0

3 years ago

Plz help with this question

Nesterboy [21]

debt is greater than 25

you owe more than 25 dollars

6 0

3 years ago

Select the pair of slopes that are the slopes of perpendicular lines.

agasfer [191]

<h3> $\frac{3}{4}\ and\ \frac{-4}{3}$ are the slopes of perpendicular lines</h3>

<em><u>Solution:</u></em>

We know that,

Product of slope of a line and slope of line perpendicular to it is always equal to -1

<em><u>Option 1</u></em>

$\frac{1}{2}\ and\ 2$

$Product = \frac{1}{2} \times 2 = 1$

Thus, these are not the slopes of perpendicular lines

<em><u>Option 2</u></em>

$\frac{3}{4}\ and\ \frac{-4}{3}\\\\Product = \frac{3}{4} \times \frac{-4}{3}\\\\Product = -1$

This option satisfies the slopes of perpendicular lines

<em><u>Option 3</u></em>

$\frac{-2}{5}\ and\ \frac{-5}{2}\\\\Product = \frac{-2}{5} \times \frac{-5}{2} = 1$

Thus, these are not the slopes of perpendicular lines

<em><u>Option 4</u></em>

2 and 2

Product = 2 x 2 = 4

Thus, these are not the slopes of perpendicular lines

7 0

3 years ago

The square root of 8?

Hoochie [10]

Answer:

√8 8n sure form= √ 4 ×√2

= 2×√2

= 2√2

8 0

3 years ago