-- Look at the places where the line crosses the 'x' axis and the 'y' axis.
Between those two points, it goes forward 2 units, but only rises 1 unit.
So the slope of the line is 1/2 .
-- Look again at the point where the line crosses the y-axis.
At that point, y=1 .
That's the "y-intercept".
Now you have the slope and y-intercept of the line.
The equation of ANY straight line is
y = (slope)x + (y-intercept) .
You know what they both are, so you can easily write
y = 1/2 x + 1 .
Is that one of the choices ?
Yes it is.
Good enough for me.
That must be the correct one.
With no "blah blah blah" required.
Answer:
3(5x-y)
Step-by-step explanation:
The common factor in 15 and 3 is 3 so you take that out
B+ 11/3= -2
⇒ b= -2 -11/3
⇒ b= -6/3 -11/3
⇒ b= -17/3
⇒ b= -5 2/3
Final answer: b= -5 2/3~
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Answer: Choice C) 
</h3>
This is a more complicated way to write 
The range is the set of all possible y outputs of a function. So we use the graph to see what y values are possible. The graph shows that y can be anything smaller than y = 2. We can't actually reach y = 2 itself due to a horizontal asymptote here.
In interval notation, the answer would be
with the curved parenthesis to indicate "do not include y = 2 as part of the range".
The equation used above is y-intercept form.
ex. y = mx + b
Whatever is in front of the x is your slope.
Your slope is -3