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Mrac [35]
3 years ago
13

Connor is playing a card game called At Face Value. At the end of each round, players earn positive points for their remaining n

umber cards but negative points for their face cards. At the end of round 1, Connor earns
–5 points. At the end of round 2, he earns –6 points. What is Connor's score now?
Mathematics
1 answer:
murzikaleks [220]3 years ago
6 0

Answer:

Kufoyfiyfiyfo6fuphihuhgugitdti5d

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3 years ago
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The costs of different weights of onions sold at a grocery store are shown in the table below. What are the independent and depe
Furkat [3]

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Independant = onions wight. Dependent = cost.

Step-by-step explanation: The Cost depends on how much the onions weight.

3 0
3 years ago
a model of an apartment is shown 1\4 in. represents 3 feet in the actual apartment. Find the actual area of the master bedroom
Hatshy [7]

Answer:12 feet by 9 feet


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8 0
3 years ago
A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe
Finger [1]

Answer:

<em>Fencing required = 1586 m</em>

Step-by-step explanation:

The given statements can be thought of a triangle \triangle ABC as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

\angle A =49^\circ

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use <em>Cosine Rule </em>to find the third side.

Formula for cosine rule:

cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}

Where  

a is the side opposite to \angle A

b is the side opposite to \angle B

c is the side opposite to \angle C

\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = <em>1586 m</em>

<em></em>

<em>Fencing required = 1586 m</em>

4 0
3 years ago
30 tens - 3 tens 3 tenths
lubasha [3.4K]
300-30.3=269.7 because you barrow from 3 in 300 because you can't round into 0 and that equalled 7 and than you do 9-0=9 and there's 009.7 than you do 9-3=6 and that's 069.7 and you do 2-0=2 and there's 269.7
4 0
3 years ago
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