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finlep [7]
3 years ago
12

Hey friends, What is a IT form? thanks

Computers and Technology
1 answer:
ziro4ka [17]3 years ago
8 0

Hi buddy, an IT form is for people who are applying at a TECH college.

Love u <3

Hope this helps

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Alexei was given a key to a substitution cipher. The key showed that the entire alphabet was rotated 13 steps. What type of ciph
larisa [96]

Answer:

ROT13

Explanation:

8 0
3 years ago
"Create a Matlab Scrapt that will take the a Matrix A and Matrix B (of AX=B), then calculate the Determinant of Matrix A, Invers
prohojiy [21]

Answer:

see explaination

Explanation:

function [] =

inverse(A,B)

da = det(A);

disp("The det of A is");

disp(da);

inva = inv(A);

disp("The inverse of A is");

disp(inva);

x = inva*B;

disp("The value of X is");

disp(x);

rk = rank(A);

disp("The rank of X is");

disp(rk);

Di = eig(A);

disp("The eigen values of A is");

disp(Di);

[V,Di] = eig(A);

disp("The eigen vectors of A are (Each column represents one column vector)");

disp(V);

end

A = [1,2;4,5];

B = [1,2;4,5];

inverse(A,B);

%ab = [num2str(t)," ",num2str(dx)," ",num2str(dy)];

%disp(ab);

4 0
3 years ago
I love science its my favorite subject
Charra [1.4K]

Answer:

Nice!

Explanation:

i like physics and biology :)

4 0
2 years ago
Read 2 more answers
DO NOT ANSWER FOR JUST POINTS
Elza [17]

Answer:

E.

a medium dashed line

Explanation:

I always use medium hehe so I think that'll work.

5 0
2 years ago
Read 2 more answers
A signal travels from point A to point B. At point A, the signal power is 100 W. At point B, the power is 90 W. What is the atte
11Alexandr11 [23.1K]

Answer:

Attenuation = 0.458\ db

Explanation:

Given

Power at point A = 100W

Power at point B = 90W

Required

Determine the attenuation in decibels

Attenuation is calculated using the following formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Where P_s = Power\ Input and P_d  = Power\ output

P_s = 100W

P_d = 90W

Substitute these values in the given formula

Attenuation = 10Log_{10}\frac{P_s}{P_d}

Attenuation = 10Log_{10}\frac{100}{90}

Attenuation = 10 * 0.04575749056

Attenuation = 0.4575749056

Attenuation = 0.458\ db <em>(Approximated)</em>

7 0
3 years ago
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