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ryzh [129]
3 years ago
7

Is a factor a part of a multiplication sentence or not.

Mathematics
1 answer:
Lorico [155]3 years ago
3 0
A factor is part of a multiplication sentence because a factor are two numbers that are multiplied togethe to get the product ( the answer ) for example: 3 multiplied by 2 = 6 3 and 2 would be the factors and 6 would be the product. Hope this helped! :D
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Using the Associative Property which expression is equivalent to (2+x)+4=
Anna35 [415]

Answer:

x+6

Step-by-step explanation:

The given expression is (2+x)+4.

The associative property is :

(a+b)+c= a+(b+c)

Here,

a = 2, b = x and c = 4

So,

(2+x)+4 = 2+(x+4)

= x+6

So, the equivalent expression is x+6.

6 0
3 years ago
A Turing machine with doubly infinite tape is similar to an ordinary Turing machine, but its tape is infinite to the left as wella
atroni [7]

Answer:

Use multitape Turing machine to simulate doubly infinite one

Explanation:

It is obvious that Turing machine with doubly infinite tape can simulate ordinary TM. For the other direction, note that 2-tape Turing machine is essentially itself a Turing machine with doubly (double) infinite tape. When it reaches the left-hand side end of first tape, it switches to the second one, and vice versa.

8 0
3 years ago
How do you find the center of dilation for a negetive dilation?​
Andrei [34K]

the Answer:

Notice that the "image" triangles are on the opposite side of the center of the dilation (vertices are on opposite side of O from the preimage). Also, notice that the triangles have been rotated 180º.

Step-by-step explanation:

A dilation is a transformation that produces an image that is the same shape as the original but is a different size. The description of a dilation includes the scale factor (constant of dilation) and the center of the dilation. The center of dilation is a fixed point in the plane about which all points are expanded or contracted. The center is the only invariant (not changing) point under a dilation (k ≠1), and may be located inside, outside, or on a figure.

Note:

A dilation is NOT referred to as a rigid transformation (or isometry) because the image is NOT necessarily the same size as the pre-image (and rigid transformations preserve length).

What happens when scale factor k is a negative value?

If the value of scale factor k is negative, the dilation takes place in the opposite direction from the center of dilation on the same straight line containing the center and the pre-image point. (This "opposite" placement may be referred to as being a " directed segment" since it has the property of being located in a specific "direction" in relation to the center of dilation.)

Let's see how a negative dilation affects a triangle:

Notice that the "image" triangles are on the opposite side of the center of the dilation (vertices are on opposite side of O from the preimage). Also, notice that the triangles have been rotated 180º.

5 0
2 years ago
Read 2 more answers
This equation which is || = -10 ?
sesenic [268]

Answer:

10

Step-by-step explanation:

7 0
3 years ago
Given that 'n' is a natural number. Prove that the equation below is true using mathematical induction.
LenaWriter [7]

<h3>To ProvE :- </h3>

  • 1 + 3 + 5 + ..... + (2n - 1) = n²

<u>Method</u><u> </u><u>:</u><u>-</u>

If P(n) is a statement such that ,

  1. P(n) is true for n = 1
  2. P(n) is true for n = k + 1 , when it's true for n = k ( k is a natural number ) , then the statement is true for all natural numbers .

\sf\to \textsf{ Let P(n) :  1 + 3 + 5 + $\dots$ +(2n-1) = n$^{\sf 2}$ }

Step 1 : <u>Put </u><u>n </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\longrightarrow LHS = \boxed{\sf 1 } \\

\sf\longrightarrow RHS = n^2 = 1^2 = \boxed{\sf 1 }

Step 2 : <u>Assume </u><u>that </u><u>P(</u><u>n)</u><u> </u><u>is </u><u>true </u><u>for </u><u>n </u><u>=</u><u> </u><u>k </u><u>:</u><u>-</u>

\sf\longrightarrow 1 + 3 + 5 + \dots + (2k - 1 ) = k^2

  • Add (2k +1) to both sides .

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+1)=k^2+(2k+1)

  • RHS is in the form of ( a + b)² = a²+b²+2ab .

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+1)= (k +1)^2

  • Adding and subtracting 1 to LHS .

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+1) + 1 -1  = (k +1)^2 \\

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+2) - 1 = (k +1)^2

  • Take out 2 as common .

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+\{2(k+1)-1\}= (k +1)^2

  • P(n) is true for n = k + 1 .

Hence by the principal of Mathematical Induction we can say that P(n) is true for all natural numbers 'n' .

<em>*</em><em>*</em><em>Edits</em><em> are</em><em> welcomed</em><em>*</em><em>*</em>

8 0
2 years ago
Read 2 more answers
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