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gayaneshka [121]
3 years ago
12

I'm thinking of a three digit number it is an odd multiple of threes and the product of its digits 24. It is larger than 15^2. W

hat are all the numbers I could be thinking of
Mathematics
1 answer:
ipn [44]3 years ago
3 0

Answer:

243, 381, 423, 813, 831

Step-by-step explanation:

The product of its digits is 24, so we have opptions:

1,3,8 because 1*3*8=24

1,4,6 becaus 1*4*6=24

2,3,4 because 2*3*4=24

2,2,6 becaus 2*2*6=24

They can be divide by 3, so the sum of its digits can be divide by 3:

1+3+8=12 (It is OK)

1+4+6=11 (It is not ok)

2+3+4=9 (it is OK)

2+2+6=10 (it is not OK).

Now we have less opportunities, it is number of digits:

1,3,8 and 2,3,4.  In wich order we will se!:)

From the informations we know that three numbers are odd number and greater then 15*15=225

Therefore, for 1,3,8 it must be that  1 ro 3 is least digit (its odd number) that numbers are:

183, 813, 831, 381

greater then 225 are 381,831,813.

For digits 2,3,4 it must be that 3 is the least digit (number is odd) so we have:

243 and 423. Both are greater than 225.

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<h3>What is Binomial distribution? </h3>

When each trial has the same probability of achieving a given value, the number of trials or observations is summarized using the binomial distribution. The likelihood of observing a specific number of successful outcomes in a specific number of trials is determined by the binomial distribution.

Computation of probability of all survived people from heart attack;

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We'll refer to a victory in this scenario as a heart attack (p = 0.04). In other words, we are interested in the likelihood that none of our n=5 patients will die (0 successes).

Each attack has a chance of being fatal or not, with a probability of 4 percent for all patients, and each patient's result is independent.

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Therefore, with a 4 % chance that anyone will die, there is an 81.54% chance that every patient will survive the onslaught. The outcomes in this example could be 0, 1, 2, 3, 4 or 5 successes (fatalities).

To know more about Binomial Distribution, here

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