3 years ago

How do I find the indicated derivative?

Mathematics

1 answer:

sergey [27]3 years ago

8 0

Multiply the fraction by both things in the parenthesis.

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8. Evaluate: f(x) = x2 + 1<br> g(x) = 5 - x<br> a. (f+g)(x) =<br> b. (f-g)(x) =

Papessa [141]

Answer:

(f+g)(x)=2x+1+5 - x

(f+g)(x)=x + 6

(f - g)(x)= 2x + 1 - (5- x )

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6 0

2 years ago

Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc

DerKrebs [107]

we are given

differential equation as

$y'''-9y''+20y'=0$

we are given

$y=e^{rx}$

Firstly, we will find y' , y'' and y'''

those are first , second and third derivative

First derivative is

$y'=re^{rx}$

Second derivative is

$y''=r*re^{rx}$

$y''=r^2e^{rx}$

Third derivative is

$y'''=r^2*re^{rx}$

$y'''=r^3e^{rx}$

now, we can plug these values into differential equation

and we get

$r^3 e^{rx}-9r^2 e^{rx}+20re^{rx}=0$

now, we can factor out common terms

$e^{rx}(r^3 -9r^2 +20r)=0$

we can move that term on right side

$(r^3 -9r^2 +20r)=0$

now, we can factor out

$r(r^2 -9r +20)=0$

$r(r-5)(r-4)=0$

now, we can set them equal

$r=0$

$r-5=0$

$r=5$

$r-4=0$

$r=4$

so, we will get

$r=0,4,5$ ...............Answer

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3 years ago

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I think it’s 16 I believe

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Read 2 more answers

Which function in vertex form is equivalent to f(x) = x2 + 8 – 16x?

damaskus [11]

Answer:

f(x)= (x+8)^2 + 200

Step-by-step explanation:

-b/2a gives you the x coordinate of the vertex and then plug it in for x to get the y coordinate. Put it in the formula (f()x= (x-h)^2 +k).

H is the x coordinate and K is the y coordinate

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allochka39001 [22]

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