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Bogdan [553]
3 years ago
13

½ (6x + 8) = 2x + 4 + x

Mathematics
2 answers:
Zarrin [17]3 years ago
6 0

Answer:

all real numbers

Step-by-step explanation:

1/2(6x + 8) = 2x + 4 + x

1/2 * 6x + 1/2 * 8 = 2x + 4 + x

3x + 4 = 2x + 4 + x

3x + 4 = 3x + 4

4 = 4

0 = 0

the answer is all real numbers because 0 will always equal 0

bearhunter [10]3 years ago
5 0

Answer:

True

Step-by-step explanation:

Both sides (right side and left side) of the equation are indeed equal.

I hope this helps!

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raketka [301]

Answer:

\text{1. } v=16t+\frac{h-c}{t},\\\text{2. }90\:\mathrm{ft/s}, \\\text{3. Cannot be determined}

Step-by-step explanation:

1. The initial equation given to us is h=-16t^2+vt+c. Rearranging the equation to isolate v, we have:

vt=16t^2+h-c,\\\boxed{v=16t+\frac{h-c}{t}}

2. Using the equation we rearranged in part 1, we can substitute given values:

v=16(3)+\frac{131-5}{3},\\v=48+42=\boxed{90\:\mathrm{ft/s}}

3. We see from our equation in part 1 (v=16t+\frac{h-c}{t}) that when t=0, the denominator of our fraction will be equal to 0. Since we cannot divide by 0, the velocity remains undefined and cannot be determined.

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2 years ago
If anyone can help with this pls do! i need to get this right thank u!
anygoal [31]
50a + 20w is greater than or equal to 350
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3 years ago
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ALGEBRA QUESTION PLS HELPS
cluponka [151]

The value of x is –7.

Solution:

Given expression:

$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}

Let us factor x^2+4x+3.

x^2+4x+3=(x+1)(x+3)

Substitute this in the fraction.

$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

To make the denominator same, multiply and divide the first term by (x +1).

$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

Denominators are same, you can add the fractions.

$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}

Cancel the common term in the numerator and denominator.

$\frac{x+7}{x+1} \cdot \frac{1}{x+1}

Multiply the fractions.

$\frac{x+7}{(x+1)^2}

$\frac{x+7}{x^2+2x+1}

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$\frac{x+7}{x^2+2x+1}=0

Do cross multiplication.

${x+7}=0\times (}{x^2+2x+1})

Any number or variable multiplied by 0 gives 0.

${x+7}=0

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${x+7-7}=0-7

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The value of x is –7.

7 0
3 years ago
The two rectangular prisms are similar.
Sophie [7]

Answer:

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Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

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y=24\ cm^{3}

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storchak [24]

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Why wouldn't it be true for tenths ?

Let me say it another way:

No.  3/10  is <em>less than</em>  5/10 .


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