Answer:
Recursive rule for arithmetic sequence = an = a[n-1] + 3
Step-by-step explanation:
Given arithmetic sequence;
-7, -4, -1, 2, 5, …
Find:
Recursive rule for arithmetic sequence;
Computation:
Let a1 = -7
So,
⇒ a2 = a1 + 3 = -4
⇒ a3 = a2 + 3 = -1
⇒ a4 = a3 + 3 = 2
⇒ a5 = a4 + 3 = 5
So, the recursive formula is
⇒ an = a[n-1] + 3
Recursive rule for arithmetic sequence = an = a[n-1] + 3
Answer:
-3 + n = 6n + 22
-1n on both sides
-3=5n+22
-22 on both sides
-25=5n
divided by 5
-5=n
Step-by-step explanation:
Answer:
I think it's true
Step-by-step explanation:
Answer:
216
Step-by-step explanation:
hindi pa sure pero yan
You'll want to use the quadratic formula:
-b (+/-) sqrt(b^2 - 4ac), all divided by 2a.
Under the square root you'll get:
-11
remember that the square root of -1 is i.
sqrt(-11) can be factored to sqrt(11*-1) and then sqrt(-1) * sqrt(11)
which becomes i*sqrt(11)
so your complex solution is:
-3 (+/-) (i*sqrt(11)), all over 4
